February 16th, 2018, 12:51 PM  #1 
Newbie Joined: Feb 2018 From: Roman, Romania Posts: 2 Thanks: 0  Triangle inequality
Let ABC a triangle and O I H are noncollinear. R₁ is radius of circumscribed circle of OIH. Show that R₁>R/2, where R is radius of circumscribed circle of ABC.
Last edited by skipjack; February 16th, 2018 at 02:41 PM. 
February 16th, 2018, 01:02 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,454 Thanks: 567 
What are O I H? How do they relate to the triangle?
Last edited by greg1313; February 16th, 2018 at 11:26 PM. 
February 16th, 2018, 01:08 PM  #3 
Newbie Joined: Feb 2018 From: Roman, Romania Posts: 2 Thanks: 0 
H = orthocentre I= incentre O = circumcentre 

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inequality, triangle 
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