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February 14th, 2018, 01:42 AM   #1
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Proof

A quadrilateral with vertices A(-b,-a),B(b,-a),C(b,a)and
D(-b,a)is given A point P(x,y) is taken on the same plane with ABCD show that PA^2+PC^2=PB^2+PD^2
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February 14th, 2018, 03:18 AM   #2
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Hi Marva. I think the quadrilateral is a rectangle.

Can you use the Pythagorean theorem to complete the problem?
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Last edited by greg1313; February 14th, 2018 at 04:55 AM.
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