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 February 13th, 2018, 08:37 AM #1 Member   Joined: Feb 2018 From: Iran Posts: 56 Thanks: 3 Analytic of point If the area of triangle ABC with the vertices A(3,1) B(-1,-2) and C(m,1) is five square units find the possible values of m?
 February 13th, 2018, 09:51 AM #2 Newbie   Joined: Dec 2017 From: Spain Posts: 18 Thanks: 1 Drawing that in a coordinate-system, you might notice that the point C has to lie on the function f(x)=1. The altitude to the side AC equals 3 units (=1-(-2)). Hence (using area formula: h(c)*c/2) we get: 5=c*3/2 $\ \ \ \ \ \ \$ /*(2/3) 10/3=c Now, remember that the triangle ABC can also be obtuse. Thus the point C lies on (19/3|1) or (-1/3|1). (You either subtract 10/3 from 3 or add it). We finally have: m(1)=19/3≈6,3 m(2)=-1/3≈-0,3 Last edited by skipjack; February 13th, 2018 at 05:28 PM.

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