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February 13th, 2018, 06:28 AM   #1
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Analytic geometry

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February 13th, 2018, 08:41 AM   #2
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My head is spinning...
HOW are the given vertices possible?
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February 13th, 2018, 12:13 PM   #3
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You're assuming a standard arrangement of the coordinate axes.
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February 13th, 2018, 12:48 PM   #4
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Pgram.JPG
As $P$ is the centroid of triangle $ABD$, $AP = AC/3$,
and so ($x$, $y$) = (2/3)(2, 1) + (1/3)(-1, -5) = (1, -1).
Thanks from Maschke and Elize

Last edited by skipjack; February 13th, 2018 at 01:29 PM. Reason: to add diagram
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February 13th, 2018, 01:01 PM   #5
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Quote:
Originally Posted by greg1313 View Post
You're assuming a standard arrangement of the coordinate axes.
Ahhh geezzzzz....yes, thanks Greg...
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