Geometry Geometry Math Forum

 June 1st, 2017, 10:07 PM #1 Senior Member   Joined: Nov 2015 From: hyderabad Posts: 232 Thanks: 2 Sphere and Plane intersection If $\displaystyle \beta$ is the radius of the circle of intersection of the sphere $\displaystyle x^2+y^2+z^2-2x-4y-6z+ \alpha=0$ and the plane $x+y+z=1$, then the relation between $\displaystyle \alpha$ and $\displaystyle \beta$ is : A) $\displaystyle 3 \alpha + 3 \beta^2 =17$ B) $\displaystyle 3 \alpha^2 - 3 \beta^2 =17$ C) $\displaystyle 3 \alpha^2 - 3 \beta^2 =67$ D) $\displaystyle 3 \alpha + 3 \beta^2 =67$ My Answer is Option D. Please check and let me know Thank you  Tags intersection, plane, sphere Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post BadWolf Calculus 2 May 27th, 2017 01:27 PM matteamanda Linear Algebra 3 September 19th, 2016 02:19 PM Vaki Geometry 4 September 18th, 2016 09:58 AM paul123ew Linear Algebra 1 March 22nd, 2015 06:23 PM triplekite Calculus 1 December 5th, 2012 08:16 AM

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