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April 20th, 2017, 12:22 PM   #1
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angle

Hello All

This is another of my son's math issue, for a test he needs to make tomorrow
I am assisting him , but would need some clarification here myself

http://s9.postimg.org/sj88a4p67/20_04_2017_22_18_09.png

AB = 7 , BC= 3, CG = 2 and AE=3

Q1) Find angle AEG

Q2) find the angle that diagnoal CE makes with the side AE

Thanks for any clarification here
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April 20th, 2017, 12:55 PM   #2
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Why isn't your son doing the posting?
Much easier to help that way.

Btw, had a look at your first few posts:
you were not mentioning your son then...

Last edited by Denis; April 20th, 2017 at 01:00 PM.
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April 20th, 2017, 11:23 PM   #3
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Quote:
Originally Posted by Denis View Post
Why isn't your son doing the posting?
Much easier to help that way.

Btw, had a look at your first few posts:
you were not mentioning your son then...
We live in Holland, and English is given as the 3rd or 4rth language at school.
at the age of 14 , kids are not linguistic capable to vent their issues in English(unless parents are from english descents...but we are not talking exceptions)...or if you understand Dutch . dan is het geen problematiek meer jongen. ....at least my kids are not capable to communicate on a forum level. Are canadian kids @ 14 capable communicating on french forums fluently (not hailing from quebec ofcourse)?

If you look at my previous posts, they are all elementary school stuff and nothing to do with 'me '.

I am working in the IT sector ( Scrum master & QA ) and these school stuff..I have been there in the 1980s but its all rusted now(I am 48 years). I have twins, both sons, and every now and then they come up asking assistance from me. Most I can solve ,but there are some hard eggs where I too need coaching. & Not that I am posting here every day , but this happens once in maybe 6 months- when their exams are approaching( check the frequency of my posts).

any more Proof you need.....,my linkedin profile, photograph, passport copy


*PS: this is the reason, one of my posts goes over Paid subscriptions, so that people who really need assistance do not get police probes . But I was told, this is a free knowledge spreading level , where all are welcome without having to go in lengthy explanations of reasons to be here.

and Oh..btw, I would still need the answer to my initial query, so if anyone is kind enough.
Thanks from Joppy

Last edited by hello_math; April 20th, 2017 at 11:51 PM.
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April 21st, 2017, 12:21 AM   #4
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Math Focus: Yet to find out.
Q1)

Angle AEG = angle AEF, this is because BF = CG = 2.

Draw a straight line from F to intersect the line EA, you will make a new triangle. This new triangle has height EA - FB = 1, and length AB = 7. Treat AB as the 'opposite' side, and (EA-FB) as the 'adjacent' side.

Then, $\tan(\theta) = \dfrac{7}{3-2}$. So, $\theta = \tan^{-1}(7) = 81.9^{\circ}$

Q2)

For this you need to imagine a triangle that has height AE, and a base of AC.

The length AC is the hypotenuse of the triangle ABC. $AC = \sqrt{BC^2 + AB^2} = \sqrt{58}$.

So, $\tan(\theta) = \dfrac{\sqrt{58}}{3}$. Where AE = 3.
Thanks from hello_math

Last edited by skipjack; April 21st, 2017 at 03:58 AM.
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April 21st, 2017, 02:01 AM   #5
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Thanks a ton Joppy

starting next week, the kids have their 'Meivakantie' (the annual May vacation) and I am pretty sure, this one's dedicated to you!

Last edited by skipjack; April 21st, 2017 at 03:59 AM.
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April 21st, 2017, 02:42 AM   #6
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Quote:
Originally Posted by hello_math View Post
Thanks a ton Joppy

starting next week, the kids have their 'Meivakantie' (the annual May vacation) and I am pretty sure, this one's dedicated to you !
Happy holidays!
Thanks from hello_math

Last edited by skipjack; April 21st, 2017 at 04:19 AM.
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April 21st, 2017, 04:06 AM   #7
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Quote:
Originally Posted by hello_math View Post
any more Proof you need.....,my linkedin profile, photograph, passport copy
The Internet is the Internet...
I'm a typing finger, so are you

I'll have you know that Canada is top
exporter of maple syrup and hockey sticks!

Last edited by Denis; April 21st, 2017 at 04:08 AM.
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April 21st, 2017, 04:19 AM   #8
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Quote:
Originally Posted by Joppy View Post
Angle AEG = angle AEF, this is because BF = CG = 2.
That's incorrect.
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April 21st, 2017, 04:27 AM   #9
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Quote:
Originally Posted by skipjack View Post
That's incorrect.
Ah. Indeed.
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April 21st, 2017, 04:34 AM   #10
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Come join me "in the corner"...
Bring pencil and paper: we'll play XandO's...
I start!
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