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 January 30th, 2017, 12:03 AM #1 Newbie   Joined: Jan 2017 From: mwanza tanzania Posts: 20 Thanks: 0 3y^4-32y-192=0 It has come to my notice that this equation 3y^4-32y-192=0 gives a value of (pi) a mathematical constant which is approximately to 3.1425.......can this equation be used to give a value of pi to any number of decimal places needed instead of known equation pi=circumference of a circle divide to its radius? kadomole Last edited by skipjack; February 1st, 2017 at 10:03 AM.
 January 30th, 2017, 03:11 AM #2 Global Moderator   Joined: Dec 2006 Posts: 18,544 Thanks: 1476 Whereas pi is 3.14159265358979..., your equation has solution 3.14248520690..., and so the two are rather different. To get closer to pi, your equation would need to be changed, and to get very close to pi would require very substantial changes. Thanks from topsquark
 January 30th, 2017, 07:55 PM #3 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 1,765 Thanks: 121 Math Focus: Trigonometry and Logarithm Isn't pi transcendental? Thanks from topsquark
 January 30th, 2017, 08:17 PM #4 Senior Member   Joined: May 2016 From: USA Posts: 887 Thanks: 353 As has been pointed out, $y \approx 3.14248 = 3.14159 + 0.001 -0.00011 \implies y - \pi \approx 0.0089.$ In fact, y is an algebraic number, and $\pi$ is a transcendental number so the two are not even in the same subset of the real numbers. Thanks from topsquark
 February 1st, 2017, 08:09 AM #5 Newbie   Joined: Feb 2017 From: HK Posts: 2 Thanks: 0 pi is not an algebraic number, so pi cannot be a root of any polynomial with rational coefficients.
February 11th, 2017, 07:15 AM   #6
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3y^4-32y-192=0

Quote:
 Originally Posted by kadomole simon kadomole It has come to my notice that this equation 3y^4-32y-192=0 gives a value of (pi) a mathematical constant which is approximately to 3.1425.......can this equation be used to give a value of pi to any number of decimal places needed instead of known equation pi=circumference of a circle divide to its radius? kadomole
which method is used to measure radius and circumference of circle? hence "pi"?any error?it can be proved mathematically that y="pi" satisfies 3y^4-32y-192=0 ,what is your comment?kadomole

February 11th, 2017, 07:33 AM   #7
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Quote:
 Originally Posted by Monox D. I-Fly Isn't pi transcendental?

 February 11th, 2017, 07:39 AM #8 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 11,631 Thanks: 735 Calculating pi is a bit like the guy who spent years sticking together over a million matches to come up with a miniature 'London Bridge': got queer looks, some respect for his tenacity...but only 5 bucks at the corner pawnshop.... This stupidity seems to have started in England (where else!) in the early 1900's. A British mathematician William Shanks worked it out to 707 decimal places doing calculations by hand for over 20 years. POOR BILL: an error in the 528th place was discovered in 1945...wonder if they changed the inscription on his tombstone
February 11th, 2017, 08:52 AM   #9
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Quote:
 Originally Posted by kadomole simon kadomole it can be proved mathematically that y="pi" satisfies 3y^4-32y-192=0
Ummm... no it can't. But please, show your proof that it is.

-Dan

 February 11th, 2017, 12:50 PM #10 Senior Member   Joined: May 2016 From: USA Posts: 887 Thanks: 353 Oh, for goodness' sakes. $3y^4 - 32y - 192 = 0 \implies 3.1424 < y.$ $\pi < 3.1416 \implies -\ 3.1416 < -\ \pi.$ $\therefore (3.1424 - 3.1416) < (y - \pi) \implies 0.0008 < (y - \pi) \implies$ $\pi < y - 0.0008 < y \implies \pi < y.$ $\therefore \pi \ne y.$ Thanks from topsquark

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