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 March 2nd, 2017, 08:46 AM #51 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,160 Thanks: 866 I can't believe that this thread has gone on for 50 posts. Obviously Kadomole came up with an equation that matched what he thought was "$\pi$". He simply does not know what "$\pi$" is. If he is, say, 12 or 13 years old, I would commend him for his (misguided) attempts. If he is older than that, it is really very sad.
March 2nd, 2017, 09:02 AM   #52
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Quote:
 Originally Posted by Country Boy I can't believe that this thread has gone on for 50 posts. Obviously Kadomole came up with an equation that matched what he thought was "$\pi$". He simply does not know what "$\pi$" is. If he is, say, 12 or 13 years old, I would commend him for his (misguided) attempts. If he is older than that, it is really very sad.
If you look at post #48, it is quite obvious that he does know what $\pi$ is.

We are now on post 51, and we still do not have his putative "proof." I strongly suspect that we never shall be given a look at that "proof."

March 3rd, 2017, 02:01 AM   #53
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Quote:
 Originally Posted by topsquark Okay, I'll play along.
Do as you wish, but personally I wouldn't waste your time with this silliness.

March 8th, 2017, 10:50 PM   #54
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 Originally Posted by topsquark Okay, I'll play along. $\displaystyle A_{circ} = \pi r^2 = A_{tri} = \frac{1}{2}b(2r)$ $\displaystyle b = \frac{\pi r^2}{\frac{1}{2}(2r)} = \pi r$ -Dan
You are right; now use these HINTS: {area of triangle=0.5r^2[4+[pi^2]/4]sinx=pi[r^2], sinx={8pi}/[16+[pi]^2}, draw a right-angled triangle with angle x, opposite side = 8pi, hypotenuse side = 16+pi^2, and adjacent side = plus[+] or minus [-] sqrt[[16+pi^2]]^2 - 64pi^2, obtain value of tanx from that triangle, use tanx=[2tanx/2]/[1-[tanx/2]^2], use tanx/2 = pi/4, finish on calculating value of pi. Test your pi value by drawing a right-angled triangle with sides sqrt8, sqrt8 and 4, one angle = pi/4, calculate different trigonometric ratio like sin[pi]/2, tan[pi]/4, sin[pi/4], etc. What do you comment on pi value? kadomole

Last edited by skipjack; March 8th, 2017 at 11:05 PM.

March 8th, 2017, 11:11 PM   #55
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Quote:
 Originally Posted by kadomole simon kadomole . . . finish on calculating value of pi.
How?

March 9th, 2017, 01:38 PM   #56
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Quote:
 Originally Posted by kadomole simon kadomole You are right; now use these HINTS: {area of triangle=0.5r^2[4+[pi^2]/4]sinx=pi[r^2]
The area of what triangle? The only formula I can come up with is $\displaystyle A = \frac{1}{2} ab ~ \sin(C)$ where a and b are two sides and C is the angle between them. Best guess is that you are talking about a triangle inscribed in the "top half" of your circle and x is the angle between two radii? But then where did the $\displaystyle 4 + \pi ^2 / 4$ and $\displaystyle \pi r^2$ come from?

-Dan

Last edited by skipjack; March 9th, 2017 at 02:01 PM.

March 10th, 2017, 12:12 PM   #57
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Quote:
 Originally Posted by topsquark The area of what triangle? The only formula I can come up with is $\displaystyle A = \frac{1}{2} ab ~ \sin(C)$ where a and b are two sides and C is the angle between them. Best guess is that you are talking about a triangle inscribed in the "top half" of your circle and x is the angle between two radii? But then where did the $\displaystyle 4 + \pi ^2 / 4$ and $\displaystyle \pi r^2$ come from? A diagram would be helpful. -Dan
take that half of Isoscles triangle with height=2r,and base=[pi]r/2,tanC/2=tanx/2=[pi]r/2/2r=[pi]/4 ,a=b=Hypotonuse =[r]sqrt[4+pi^2/4] , 0.5[ab]sinC=[pi]r^2kadomole

 March 10th, 2017, 12:16 PM #58 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,406 Thanks: 829 This guy is unbelievable...
March 10th, 2017, 02:15 PM   #59
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Quote:
 Originally Posted by Denis This guy is unbelievable...
well when you feed the trolls they grow

March 10th, 2017, 05:28 PM   #60
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I have chosen to intervene. I ask all other members to refrain from further discussion until the issues addressed below are resolved.

Quote:
 Originally Posted by kadomole simon kadomole It has come to my notice that this equation 3y^4-32y-192=0 gives a value of (pi) a mathematical constant which is approximately to 3.1425.......can this equation be used to give a value of pi to any number of decimal places needed instead of known equation pi=circumference of a circle divide to its radius? kadomole

As previously asked, how is this equation used to determine the value of $\pi$ (pi)? Note that $\pi\ne3.1425...$

Please respond explicitly. Do not refer to previous posts without directly quoting them. Include all relevant details. Failure to do so will result in this thread being closed.

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