February 14th, 2017, 11:44 PM  #21 
Newbie Joined: Jan 2017 From: mwanza tanzania Posts: 20 Thanks: 0  I need to change a value of your pi and retain my equation. kadomole
Last edited by skipjack; February 15th, 2017 at 02:10 PM. 
February 14th, 2017, 11:49 PM  #22  
Newbie Joined: Jan 2017 From: mwanza tanzania Posts: 20 Thanks: 0  Quote:
 
February 15th, 2017, 01:05 AM  #23 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 11,672 Thanks: 741 
Go to a nearby university and present your idea to the head math teacher... 
February 15th, 2017, 09:06 AM  #24 
Math Team Joined: May 2013 From: The Astral plane Posts: 1,669 Thanks: 657 Math Focus: Wibbly wobbly timeywimey stuff.  
February 15th, 2017, 10:09 AM  #25 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,959 Thanks: 801  Clearly the number y defined in the first post is not a transcendental number because it is the solution to a polynomial equation with integer coefficients. That is the definition of "algebraic number" while the definition of "transcendental number" is "not an algebraic number"!

February 15th, 2017, 10:17 AM  #26 
Senior Member Joined: Feb 2010 Posts: 637 Thanks: 106 
When I want $\displaystyle \pi$ (and am too tired to buy one at the local supermarket), I use the larger root of $\displaystyle 113x^2468x+355=0$.

February 15th, 2017, 11:02 AM  #27 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 11,672 Thanks: 741  
February 15th, 2017, 11:04 AM  #28 
Senior Member Joined: May 2016 From: USA Posts: 904 Thanks: 359 
He says he has a proof that his value of $\pi$ is correct. I keep waiting for that proof.

February 15th, 2017, 11:42 AM  #29 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 11,672 Thanks: 741 
Fear not Jeff, tabarnak! He draws his circles by hand... 
February 19th, 2017, 12:02 AM  #30 
Newbie Joined: Jan 2017 From: mwanza tanzania Posts: 20 Thanks: 0  

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