January 5th, 2017, 08:07 AM  #1 
Newbie Joined: Oct 2015 From: rotterdam Posts: 8 Thanks: 1  triangle problem
Who can explain to me why CP/PA = Area CPQ/Area PAQ? Thanks in advance. 
January 5th, 2017, 09:48 AM  #2 
Senior Member Joined: Mar 2011 From: Chicago, IL Posts: 214 Thanks: 77 
The triangles CPQ and PAQ have the same height (let's call it h). $\displaystyle A_{CPQ}=0.5\cdot CP\cdot h$ $\displaystyle A_{PAQ}=0.5\cdot PA\cdot h$ 
January 5th, 2017, 09:50 AM  #3 
Senior Member Joined: Feb 2010 Posts: 632 Thanks: 103 
Draw a segment from Q perpendicular to AC. Now calculate the areas of both triangles and divide.


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