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January 5th, 2017, 07:07 AM   #1
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From: rotterdam

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triangle problem

Who can explain to me why CP/PA = Area CPQ/Area PAQ?

Thanks in advance.
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January 5th, 2017, 08:48 AM   #2
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The triangles CPQ and PAQ have the same height (let's call it h).
$\displaystyle A_{CPQ}=0.5\cdot CP\cdot h$
$\displaystyle A_{PAQ}=0.5\cdot PA\cdot h$
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January 5th, 2017, 08:50 AM   #3
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Draw a segment from Q perpendicular to AC. Now calculate the areas of both triangles and divide.
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