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November 13th, 2016, 10:56 PM   #1
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Lightbulb Diagram of rhombus

Rhombus diagram, Q(-8;6), R, S and T(3:9). The equation of QS is x+3y=10.

Show that the equation of RT = 3x-y=0
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November 13th, 2016, 11:18 PM   #2
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http://www.edwardsmaths.com/wp-conte...-Paper-Eng.pdf
question 4 is the same diagram
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November 14th, 2016, 12:52 AM   #3
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The diagonals of a rhombus are perpendicular, so the product of their gradients is -1.

The gradient of QS is -1/3 so the gradient of RT is 3.

As RT contains the point (3, 9), RT has equation y = 3x (where x ∈ [-1, 3]).
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