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- - **prove that angle formed at orthocenter is supplement of the angle formed at the vertx**
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prove that angle formed at orthocenter is supplement of the angle formed at the vertxI was searching for properties of orthocentre, circumcentre, incentre etc., and I came across this statement: the angle formed at the orthocenter is the supplement of the angle at the vertex (/_BAC + /_BHC = 180°). (Here ABC is a triangle where A is the vertex I am talking about and H is the orthocentre.) Can someone kindly prove it? Thanks for your help. :D:D |

Quote:
$\displaystyle \angle BHC=90+ \angle HCA = 90 + 90 - \angle BAC$ |

The total of the interior angles in any quadrilateral add to 360 degrees. And, here, two of the angles are right angles. |

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