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April 10th, 2011, 09:41 PM   #1
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GEOMETRY PROBLEM

WHAT IS THE ANSWER...
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April 10th, 2011, 09:44 PM   #2
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Re: GEOMETRY PROBLEM

F.
As in, you will
Fail if you don't learn to do your own work.
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April 10th, 2011, 11:12 PM   #3
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F) 1 and 2 and 3
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April 11th, 2011, 06:15 AM   #4
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Re: GEOMETRY PROBLEM

Hello, khalidmustafa06!

In [1], the triangles are congruent by s.a.s.

In [3], the three corresponding angles are equal.[color=beige] .[/color]The triangle are congruent by a,s,a,


In [2], we have the "ambiguous case".

With the given information, two different triangles are possible.


Code:
                      *                           *
            14    *    *                14    *  *
              *         * 12              *     * 12
          * 55           *            * 55     *
      *   *   *   *   *   *       *   *   *   *

The answer is:[color=beige] .[/color](E) 1 and 3 only.

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April 11th, 2011, 05:43 PM   #5
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Thanks for the correction, soroban!
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April 13th, 2011, 07:27 PM   #6
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Re: GEOMETRY PROBLEM

Measure of a tangent is opposite over adjacent angles. You will need a scientific or graphing calculator.

Here's an example:
I \
I \
I_ \
I_I__\
The angle to the right of the right angle is the example I will use.
I will call it 'A'.

TAN A=opposite/adjacent. The number of the opposite and adjacent sides should be given. This is a ratio.

TAN A = ratio.

Divide by TAN (hit TAN -1: you will have to use the 2nd key) on both sides.
You will then have:

A = TAN-1 (multiplied by) ratio.

YOU MUST HAVE A CALCULATOR TO DO THIS PROBLEM.

Repeat this for the other angle you need. Then add your results, giving you the final measure of the large angle.
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April 14th, 2011, 09:08 AM   #7
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Re: GEOMETRY PROBLEM

Quote:
Originally Posted by Brendon Edmund
Measure of a tangent is opposite over adjacent angles. You will need a scientific or graphing calculator.

Here's an example:
I \
I \
I_ \
I_I__\
The angle to the right of the right angle is the example I will use.
I will call it 'A'.

TAN A=opposite/adjacent. The number of the opposite and adjacent sides should be given. This is a ratio.

TAN A = ratio.

Divide by TAN (hit TAN -1: you will have to use the 2nd key) on both sides.
You will then have:

A = TAN-1 (multiplied by) ratio.

YOU MUST HAVE A CALCULATOR TO DO THIS PROBLEM.

Repeat this for the other angle you need. Then add your results, giving you the final measure of the large angle.
You have no idea what you are talking about.
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