My Math Forum GEOMETRY PROBLEM
 User Name Remember Me? Password

 Geometry Geometry Math Forum

April 10th, 2011, 08:41 PM   #1
Newbie

Joined: Apr 2011

Posts: 9
Thanks: 0

GEOMETRY PROBLEM

WHAT IS THE ANSWER...
Attached Images
 8.PNG (10.2 KB, 196 views)

 April 10th, 2011, 08:44 PM #2 Global Moderator     Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4 Re: GEOMETRY PROBLEM F. As in, you will Fail if you don't learn to do your own work.
 April 10th, 2011, 10:12 PM #3 Senior Member   Joined: Apr 2007 Posts: 2,140 Thanks: 0 F) 1 and 2 and 3
 April 11th, 2011, 05:15 AM #4 Math Team   Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408 Re: GEOMETRY PROBLEM Hello, khalidmustafa06! In [1], the triangles are congruent by s.a.s. In [3], the three corresponding angles are equal.[color=beige] .[/color]The triangle are congruent by a,s,a, In [2], we have the "ambiguous case". With the given information, two different triangles are possible. Code: * * 14 * * 14 * * * * 12 * * 12 * 55 * * 55 * * * * * * * * * * * The answer is:[color=beige] .[/color](E) 1 and 3 only.
 April 11th, 2011, 04:43 PM #5 Senior Member   Joined: Apr 2007 Posts: 2,140 Thanks: 0 Thanks for the correction, soroban!
 April 13th, 2011, 06:27 PM #6 Newbie   Joined: Apr 2011 Posts: 3 Thanks: 0 Re: GEOMETRY PROBLEM Measure of a tangent is opposite over adjacent angles. You will need a scientific or graphing calculator. Here's an example: I \ I \ I_ \ I_I__\ The angle to the right of the right angle is the example I will use. I will call it 'A'. TAN A=opposite/adjacent. The number of the opposite and adjacent sides should be given. This is a ratio. TAN A = ratio. Divide by TAN (hit TAN -1: you will have to use the 2nd key) on both sides. You will then have: A = TAN-1 (multiplied by) ratio. YOU MUST HAVE A CALCULATOR TO DO THIS PROBLEM. Repeat this for the other angle you need. Then add your results, giving you the final measure of the large angle.
April 14th, 2011, 08:08 AM   #7
Global Moderator

Joined: Nov 2009
From: Northwest Arkansas

Posts: 2,766
Thanks: 4

Re: GEOMETRY PROBLEM

Quote:
 Originally Posted by Brendon Edmund Measure of a tangent is opposite over adjacent angles. You will need a scientific or graphing calculator. Here's an example: I \ I \ I_ \ I_I__\ The angle to the right of the right angle is the example I will use. I will call it 'A'. TAN A=opposite/adjacent. The number of the opposite and adjacent sides should be given. This is a ratio. TAN A = ratio. Divide by TAN (hit TAN -1: you will have to use the 2nd key) on both sides. You will then have: A = TAN-1 (multiplied by) ratio. YOU MUST HAVE A CALCULATOR TO DO THIS PROBLEM. Repeat this for the other angle you need. Then add your results, giving you the final measure of the large angle.
You have no idea what you are talking about.

 Tags geometry, problem

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Doc Geometry 5 January 5th, 2015 12:31 AM Ionika Geometry 0 March 2nd, 2014 11:35 AM abctony Geometry 6 May 25th, 2013 01:40 PM Eminem_Recovery Geometry 3 January 15th, 2011 01:28 AM mrhesham Geometry 2 December 7th, 2010 05:11 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top

Copyright © 2019 My Math Forum. All rights reserved.