April 10th, 2011, 09:41 PM  #1 
Newbie Joined: Apr 2011 Posts: 9 Thanks: 0  GEOMETRY PROBLEM
WHAT IS THE ANSWER...

April 10th, 2011, 09:44 PM  #2 
Global Moderator Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4  Re: GEOMETRY PROBLEM
F. As in, you will Fail if you don't learn to do your own work. 
April 10th, 2011, 11:12 PM  #3 
Senior Member Joined: Apr 2007 Posts: 2,140 Thanks: 0 
F) 1 and 2 and 3

April 11th, 2011, 06:15 AM  #4 
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 407  Re: GEOMETRY PROBLEM Hello, khalidmustafa06! In [1], the triangles are congruent by s.a.s. In [3], the three corresponding angles are equal.[color=beige] .[/color]The triangle are congruent by a,s,a, In [2], we have the "ambiguous case". With the given information, two different triangles are possible. Code: * * 14 * * 14 * * * * 12 * * 12 * 55 * * 55 * * * * * * * * * * * The answer is:[color=beige] .[/color](E) 1 and 3 only. 
April 11th, 2011, 05:43 PM  #5 
Senior Member Joined: Apr 2007 Posts: 2,140 Thanks: 0 
Thanks for the correction, soroban!

April 13th, 2011, 07:27 PM  #6 
Newbie Joined: Apr 2011 Posts: 3 Thanks: 0  Re: GEOMETRY PROBLEM
Measure of a tangent is opposite over adjacent angles. You will need a scientific or graphing calculator. Here's an example: I \ I \ I_ \ I_I__\ The angle to the right of the right angle is the example I will use. I will call it 'A'. TAN A=opposite/adjacent. The number of the opposite and adjacent sides should be given. This is a ratio. TAN A = ratio. Divide by TAN (hit TAN 1: you will have to use the 2nd key) on both sides. You will then have: A = TAN1 (multiplied by) ratio. YOU MUST HAVE A CALCULATOR TO DO THIS PROBLEM. Repeat this for the other angle you need. Then add your results, giving you the final measure of the large angle. 
April 14th, 2011, 09:08 AM  #7  
Global Moderator Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4  Re: GEOMETRY PROBLEM Quote:
 

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