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April 10th, 2011, 02:01 AM   #1
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geometry

SOME HELP
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khalidmustafa06 is offline  
 
April 10th, 2011, 06:32 AM   #2
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Re: geometry

1) angle CAB = angle CBD
therefore the two triangles are similar, triangle CAB & triangle CBD
the ration of the sides must be equal
2) Lets AD = x, then AC = (x+3)
3) ( BC / AC ) = ( DC / BC)
( 5 / (x+3)) = ( 3 / 5 )
cross multiple:
3x + 9 = 25

x = (25 - 9) / 3
x= 5.333

answer is C) 5 1/3
SameOldHat is offline  
April 10th, 2011, 06:41 AM   #3
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Re: geometry

Hello, khalidmustafa06!

Quote:




[color=beige]. . [/color]

Code:
                        B
                        *
                     * @|*
                  *     | *
               *       4|  * 5
            *           |   *
         *              |  @ *
    A * - - - - - - - - * - - * C
                        D  3












soroban is offline  
April 13th, 2011, 06:30 PM   #4
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Re: geometry

Measure of a tangent is opposite over adjacent angles. You will need a scientific or graphing calculator.

Here's an example:
I \
I \
I_ \
I_I__\
The angle to the right of the right angle is the example I will use.
I will call it 'A'.

TAN A=opposite/adjacent. The number of the opposite and adjacent sides should be given. This is a ratio.

TAN A = ratio.

Divide by TAN (hit TAN -1: you will have to use the 2nd key) on both sides.
You will then have:

A = TAN-1 (multiplied by) ratio.

YOU MUST HAVE A CALCULATOR TO DO THIS PROBLEM.

Repeat this for the other angle you need. Then add your results, giving you the final measure of the large angle.
Brendon Edmund is offline  
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