April 10th, 2011, 02:01 AM  #1 
Newbie Joined: Apr 2011 Posts: 9 Thanks: 0  geometry
SOME HELP

April 10th, 2011, 06:32 AM  #2 
Newbie Joined: Apr 2011 Posts: 6 Thanks: 0  Re: geometry
1) angle CAB = angle CBD therefore the two triangles are similar, triangle CAB & triangle CBD the ration of the sides must be equal 2) Lets AD = x, then AC = (x+3) 3) ( BC / AC ) = ( DC / BC) ( 5 / (x+3)) = ( 3 / 5 ) cross multiple: 3x + 9 = 25 x = (25  9) / 3 x= 5.333 answer is C) 5 1/3 
April 10th, 2011, 06:41 AM  #3  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Re: geometry Hello, khalidmustafa06! Quote:
 
April 13th, 2011, 06:30 PM  #4 
Newbie Joined: Apr 2011 Posts: 3 Thanks: 0  Re: geometry
Measure of a tangent is opposite over adjacent angles. You will need a scientific or graphing calculator. Here's an example: I \ I \ I_ \ I_I__\ The angle to the right of the right angle is the example I will use. I will call it 'A'. TAN A=opposite/adjacent. The number of the opposite and adjacent sides should be given. This is a ratio. TAN A = ratio. Divide by TAN (hit TAN 1: you will have to use the 2nd key) on both sides. You will then have: A = TAN1 (multiplied by) ratio. YOU MUST HAVE A CALCULATOR TO DO THIS PROBLEM. Repeat this for the other angle you need. Then add your results, giving you the final measure of the large angle. 

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