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 July 15th, 2010, 10:38 AM #1 Senior Member   Joined: Apr 2009 Posts: 106 Thanks: 0 Analytical Geometry Given P(-2, 3) and circle (x-3)^2 + (y-3)^2 = 9, find the tangents (of the circle) through P.
 July 15th, 2010, 11:42 AM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond Re: Analytical Geometry The distance from the point (-2, 3) to the center of the circle is 5. The distance from the center of the circle to the point of tangency is 3. So, by Pythagoras, the distance from (-2, 3) to the point of tangency (x, y) is 4, and that gives us the equation (x + 2)^2 + (y - 3)^2 = 16. From this equation subtract the equation of the circle and solve for x. That will give you the x-coordinate of the point where the tangent meets the circle. Can you finish?
 July 17th, 2010, 01:06 PM #3 Senior Member   Joined: Apr 2009 Posts: 106 Thanks: 0 Re: Analytical Geometry Yes. Thank you very much

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