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 July 15th, 2010, 10:38 AM #1 Senior Member   Joined: Apr 2009 Posts: 106 Thanks: 0 Analytical Geometry Given P(-2, 3) and circle (x-3)^2 + (y-3)^2 = 9, find the tangents (of the circle) through P. July 15th, 2010, 11:42 AM #2 Global Moderator   Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond Re: Analytical Geometry The distance from the point (-2, 3) to the center of the circle is 5. The distance from the center of the circle to the point of tangency is 3. So, by Pythagoras, the distance from (-2, 3) to the point of tangency (x, y) is 4, and that gives us the equation (x + 2)^2 + (y - 3)^2 = 16. From this equation subtract the equation of the circle and solve for x. That will give you the x-coordinate of the point where the tangent meets the circle. Can you finish? July 17th, 2010, 01:06 PM #3 Senior Member   Joined: Apr 2009 Posts: 106 Thanks: 0 Re: Analytical Geometry Yes. Thank you very much Tags analytical, geometry Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post jSasor Geometry 2 December 13th, 2013 09:24 AM tomkoolen Geometry 0 January 24th, 2013 02:42 PM munkifisht Calculus 2 June 13th, 2012 12:02 PM finfanillo Linear Algebra 0 March 21st, 2012 10:14 PM manich44 Algebra 11 January 27th, 2010 09:00 AM

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