
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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May 31st, 2009, 11:10 AM  #1 
Newbie Joined: May 2009 Posts: 2 Thanks: 0  terms of a over b
The terms of a/b are a, and 1/b. WHY? Shouldn't the terms be just a and b?

May 31st, 2009, 12:02 PM  #2 
Newbie Joined: May 2009 Posts: 5 Thanks: 0  Re: terms of a over b
a/b a/1 = a 1/b = b must remain in the denominator 
May 31st, 2009, 05:17 PM  #3  
Senior Member Joined: Jul 2008 Posts: 895 Thanks: 0  Re: terms of a over b Quote:
 
July 27th, 2009, 11:48 PM  #4 
Newbie Joined: May 2009 Posts: 7 Thanks: 0  Re: terms of a over b
The terms of a fraction are: the nominator and the denominator. First one is the number written "above" the fraction, and the other one is "below" and is used when doing the least common factor. So, when having the fraction a/b, the terms of this expression are a and b. And that' s all.

August 25th, 2009, 08:32 AM  #5  
Senior Member Joined: Jul 2008 Posts: 895 Thanks: 0  Re: terms of a over b Quote:
If you had (ab + 1)/b, that could be rewritten as a + (1/b), and you'd have an expression in terms of a and b, as is the original, or in terms of a and (1/b), as you wish. You see, you can form an expression "in terms of" anything you like, so long as it is consistent with an original expression. The thing would be to not mix them up. If wanting in terms of a and (1/b), the original would not do, and you'd have had to changed it to suit as in the second expression. Sounds like a bunch of gobbledegook, but it's not if you stop and think about it.  
September 24th, 2009, 03:50 AM  #6 
Newbie Joined: Sep 2009 Posts: 27 Thanks: 1  Re: terms of a over b
If you consider a*(1/b) = a/b, then the terms of the first could be considered as a and (1/b). However, I do agree with mathpedia that the terms of a/b are a and b for simplicity's sake. In essence, I'd assume they're both correct 

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