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April 8th, 2015, 01:17 PM  #1 
Member Joined: Jan 2015 From: Norway Posts: 95 Thanks: 1  Polynom regression temperature in the the atmosphere
Temperature in the atmosphere variates much because the ozon layer and greenhouse effect affects the different air layers. On a particular location right between equator is the temperature T(X) one day measured in different heights x over the ground. The table shows some of the result : A)Find the regression on a third grade function: T(x)= 0.0025x^3 + 0.2875x^2  8.9375x + 37,8125. B) What was the temperature on the ground that day? I can't find an answer to that, i am stuck there. I don't know how to calculate that. 
April 10th, 2015, 05:11 AM  #2 
Senior Member Joined: Apr 2014 From: Glasgow Posts: 2,157 Thanks: 731 Math Focus: Physics, mathematical modelling, numerical and computational solutions 
x is the height, so what is x at ground level? 
April 10th, 2015, 12:18 PM  #3 
Member Joined: Jan 2015 From: Norway Posts: 95 Thanks: 1 
It's 0. There is no height in the ground and that means it's 0. You do T(0) and end up with + 37,8175 = 38 Degrees,
Last edited by Zman15; April 10th, 2015 at 12:28 PM. 

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atmosphere, polynom, regression, temperature 
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