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 Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion

 April 8th, 2015, 12:11 PM #1 Newbie   Joined: Apr 2015 From: London Posts: 1 Thanks: 0 Set Percentage then a set figure Hi, I am completely useless as maths, so I know this forum is my haven! Basically, I use a software which allows me to automatically increase a price from one source to another source based on a % increase from the original price. My problem is probably very easy to answer; basically, I have 2 percentages to add and then a set £0.20, so for example: 7% + 3.4% = 10.4% + 20p, but I need this to be in one % of the original figure, is this possible? Many thanks in advance. Last edited by skipjack; April 9th, 2015 at 03:20 AM. April 8th, 2015, 01:16 PM   #2
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 Originally Posted by medievil2003 Hi, I am completely useless as maths, so I know this forum is my haven! Basically, I use a software which allows me to automatically increase a price from one source to another source based on a % increase from the original price. My problem is probably very easy to answer; basically, I have 2 percentages to add and then a set £0.20, so for example: 7% + 3.4% = 10.4% + 20p, but I need this to be in one % of the original figure, is this possible? Many thanks in advance.
Yes, as long as you know the original price.

Last edited by skipjack; April 9th, 2015 at 03:21 AM. April 9th, 2015, 01:46 AM #3 Senior Member   Joined: Apr 2014 From: Glasgow Posts: 2,161 Thanks: 734 Math Focus: Physics, mathematical modelling, numerical and computational solutions How's your algebra? An algebraic function describing what you stated is: $\displaystyle P_{new} = \left(1+ \frac{p_i}{100\%}\right)P_{old} + P_{add}$ where $\displaystyle P_{new}$ = new price of item $\displaystyle P_{old}$ = old/original price of item $\displaystyle p_i$ = percentage increase (e.g. 15%) $\displaystyle P_{add}$ = price to add Then the net percentage increase after the operation above is given by $\displaystyle p_{net} = \left(\frac{P_{new}}{P_{old}} - 1\right) \times 100 \%$ For example, using the numbers you gave... $\displaystyle p_i = 10.4\%$ $\displaystyle P_{add} = 20$p and some old price... let's say $\displaystyle P_{old} = 80$p $\displaystyle P_{new} = \left(1+ \frac{10.4\%}{100\%}\right)\times 80 + 20$ $\displaystyle = (1.104 \times 80) + 20$ $\displaystyle = 108.32$p We can now calculate the net percentage increase: $\displaystyle p_{net} = \left(\frac{108.32}{80} - 1\right) \times 100\%$ $\displaystyle =(1.354 - 1) \times 100 \%$ $\displaystyle = 35.4\%$ Last edited by Benit13; April 9th, 2015 at 01:56 AM. Tags figure, percentage, set Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post rdaloian Algebra 5 January 17th, 2015 07:18 PM mared Geometry 1 July 6th, 2014 03:16 AM himybrother Real Analysis 2 October 19th, 2009 04:24 PM Al_Ch Elementary Math 2 May 21st, 2009 05:53 PM flyaway Algebra 6 March 10th, 2009 08:42 PM

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