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November 22nd, 2014, 01:52 AM   #1
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Simplification

Hi, can someone simplify this for me please. I seem to miss something when doing it

$\displaystyle

\frac{(3a^2b^3)^{1/2} * (4a^2b^6)^{-1/3}}{(24a^2b^2)^{1/2}}

$


The answer is:

$\displaystyle
\frac{1}{2^{13/6}a^{2/3}b^{3/2}}
$

I think that I'm doing something wrong with the 24 or something like that

Thank you for your time.

Last edited by skipjack; November 22nd, 2014 at 03:54 AM.
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November 22nd, 2014, 04:00 AM   #2
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The answer you posted is correct. If you post your working, we can identify any mistakes you made.

You need to cancel 3 at some stage, so the 24 becomes 8 (or 2³).
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November 22nd, 2014, 04:33 AM   #3
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Thanks for the reply

I'll post the first steps and you can check if it's good or not and i'll move on to the rest because my final answer is completely different from the correct one.

$\displaystyle
= \frac {3^\tfrac{1}{2} ab^\tfrac{3}{2} * 4^\tfrac{-1}{3}b^{-2}}{(2^3)^\tfrac{1}{2}ab}

=\frac {3^\tfrac{1}{2} ab^\tfrac{3}{2} }{(2^3)^\tfrac{1}{2}ab * 4^\tfrac{1}{3}b^{2}}
$
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November 22nd, 2014, 08:30 AM   #4
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Why did you replace 24 with $2^3$? Why did $a^2$ in the second part of the numerator just disappear instead of becoming $a^{-2/3}$?
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November 22nd, 2014, 09:15 AM   #5
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I'm sorry for the missing <a>, I'm just getting used to post using the latex commands and I get confused when using it.

I don't know what to do with $\displaystyle 24^{1/2}$


**to make a long story short, I touched math again after a very long time and found a book, started working on the problems but there are not many explanations in it

Last edited by skipjack; November 22nd, 2014 at 11:12 AM.
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November 22nd, 2014, 11:14 AM   #6
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$\displaystyle 24^{1/2} = 3^{1/2}8^{1/2}$
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