
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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November 10th, 2014, 11:06 AM  #1 
Member Joined: Sep 2010 From: Europe Posts: 45 Thanks: 1  Table of values/Value table
Hello again, dear "math lovers"(at least some of you.. )! So, my last post was about the same issue. However, now I got a different equation. X2(X1) = 382  2X1. What I have troubles with is to decide what the interval should be in the table, and how I can work my way/calculate the right values. My "draft" is somewhat like this: x1:050100150 x2(x1): 38228218282 I can try to explain why I think this way: Reason: Lets jump to X1 = 50 > 382  (2*50) = 282. X1 = 100 > 382  (2*100) = 182 X1 = 150 > 382  (2*150) = 82 Is this right? If so, please say gz. If not, tell me in a human way why not. Thanks! Best regards, Pumaftw Last edited by Pumaftw; November 10th, 2014 at 11:15 AM. 
November 10th, 2014, 11:36 AM  #2 
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361 
gz

November 10th, 2014, 11:57 AM  #3 
Member Joined: Sep 2010 From: Europe Posts: 45 Thanks: 1 
Yea, I thought I were right. But, the teacher wrote this in his solutions: X1 = 50 > X2(X1) = 182 X1 = 100 > X2(X1) = 100 X1 = 150 > X2(X1) = 82 Who's right, him or me? Also, Google disagrees with me. Google also cheer for my teacher. My coordinate system will be wrong. If you type my equation in Google, you'll get the same coordinate system as my teacher proposed/said according to the solutions. 
November 10th, 2014, 12:20 PM  #4 
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361 
Looks to me like X2 is a function of X1. Is it?

November 10th, 2014, 12:36 PM  #5 
Member Joined: Sep 2010 From: Europe Posts: 45 Thanks: 1 
X1 is the number of produced product of type/variant 1 X2 is the number of produced water tanks of type/variant 2. If that helps.. 
November 10th, 2014, 01:43 PM  #6 
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361 
Not to me. Could you give the full exercise?

November 11th, 2014, 11:42 AM  #7 
Member Joined: Sep 2010 From: Europe Posts: 45 Thanks: 1 
My mistake. After reading the exercise you are right. It(X2) is a function of X1. Additional information(I don't know if it's relevant or not): X2(X1) = 300  X1 X2(X1) = 382  2X1 X2(X1) = 250  7/9 X1 So yea, I'm supposed to make three tables, but I was thinking just of telling you guys one of the equation so I could try to solve the others myself. Edit: The following information are just basic information I had in the beginning. The information above is the same as below, just I made the inequalities to equalities and divided X1 on both sides(and moved X1 to the other side).: X1 + X2 <_ 300 8X1 + 4X2 <_ 1528 14X1 + 18X2 <_ 4500 Last edited by Pumaftw; November 11th, 2014 at 11:53 AM. 
November 11th, 2014, 02:43 PM  #8 
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361 
Not sure what you mean. Are you saying that if X2(X1) means that X2 is a function of X1 then dividing by X1 gives X2?

November 12th, 2014, 10:15 AM  #9 
Member Joined: Sep 2010 From: Europe Posts: 45 Thanks: 1 
This is my second equation in my previous post. And this is how I solved it. 8X1 + 4X2 = 1528 4X2 = 1528  8X1 : /4 both sides X2(X1) = 382  2X1 Now, I have to put this in the table, but I don't know how I should proceed. 
November 12th, 2014, 11:13 AM  #10 
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361 
You've already made a table for it. Maybe you could include X1 such that X2 is zero.


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