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November 10th, 2014, 11:06 AM   #1
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Table of values/Value table

Hello again, dear "math lovers"(at least some of you.. )!

So, my last post was about the same issue. However, now I got a different equation.

X2(X1) = 382 - 2X1.

What I have troubles with is to decide what the interval should be in the table, and how I can work my way/calculate the right values.

My "draft" is somewhat like this:

x1:-------0----50---100--150
x2(x1): 382--282--182---82

I can try to explain why I think this way:

-----------------------------Reason:
Lets jump to X1 = 50 -> 382 - (2*50) = 282.
---------------X1 = 100 -> 382 - (2*100) = 182
---------------X1 = 150 -> 382 - (2*150) = 82

Is this right? If so, please say gz. If not, tell me in a human way why not.

Thanks!

Best regards,
Pumaftw

Last edited by Pumaftw; November 10th, 2014 at 11:15 AM.
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November 10th, 2014, 11:36 AM   #2
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gz
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November 10th, 2014, 11:57 AM   #3
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Yea, I thought I were right. But, the teacher wrote this in his solutions:

X1 = 50 -> X2(X1) = 182
X1 = 100 -> X2(X1) = 100
X1 = 150 -> X2(X1) = 82

Who's right, him or me?

Also, Google disagrees with me. Google also cheer for my teacher. My coordinate system will be wrong. If you type my equation in Google, you'll get the same coordinate system as my teacher proposed/said according to the solutions.
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November 10th, 2014, 12:20 PM   #4
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Looks to me like X2 is a function of X1. Is it?
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November 10th, 2014, 12:36 PM   #5
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X1 is the number of produced product of type/variant 1
X2 is the number of produced water tanks of type/variant 2.

If that helps..
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November 10th, 2014, 01:43 PM   #6
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Not to me. Could you give the full exercise?
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November 11th, 2014, 11:42 AM   #7
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My mistake. After reading the exercise you are right. It(X2) is a function of X1.

Additional information(I don't know if it's relevant or not):

X2(X1) = 300 - X1
X2(X1) = 382 - 2X1
X2(X1) = 250 - 7/9 X1

So yea, I'm supposed to make three tables, but I was thinking just of telling you guys one of the equation so I could try to solve the others myself.

Edit: The following information are just basic information I had in the beginning. The information above is the same as below, just I made the inequalities to equalities and divided X1 on both sides(and moved X1 to the other side).:

X1 + X2 <_ 300
8X1 + 4X2 <_ 1528
14X1 + 18X2 <_ 4500

Last edited by Pumaftw; November 11th, 2014 at 11:53 AM.
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November 11th, 2014, 02:43 PM   #8
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Not sure what you mean. Are you saying that if X2(X1) means that X2 is a function of X1 then dividing by X1 gives X2?
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November 12th, 2014, 10:15 AM   #9
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This is my second equation in my previous post. And this is how I solved it.

8X1 + 4X2 = 1528
4X2 = 1528 - 8X1 : /4 both sides
X2(X1) = 382 - 2X1

Now, I have to put this in the table, but I don't know how I should proceed.
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November 12th, 2014, 11:13 AM   #10
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You've already made a table for it. Maybe you could include X1 such that X2 is zero.
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