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October 13th, 2014, 09:28 PM   #1
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What percentage of the mixure is water?

If 3 gallons of spirit containing 20% water are added to 5 gallons of another spirit containing 15% water, what percentage of the mixure is water?
How do I tackle this problem?
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October 13th, 2014, 09:54 PM   #2
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$\displaystyle \frac{0.6+0.75}{8}=0.16875$
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October 13th, 2014, 10:12 PM   #3
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How did you do it?
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October 13th, 2014, 10:22 PM   #4
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20% of 3 is 0.6. 15% of 5 is 0.75. Adding these gives how much water is in 8 gallons of the mixture.
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October 13th, 2014, 11:17 PM   #5
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I got 16.875%.
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October 13th, 2014, 11:20 PM   #6
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That's correct.
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October 13th, 2014, 11:44 PM   #7
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Thank you.
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