My Math Forum Very... Trivial Fraction Question

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 October 8th, 2014, 05:20 AM #1 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry Very... Trivial Fraction Question The value of $\displaystyle (\frac{4}{3}:\frac{1}{3})\times\frac{1}{2}=...$ A. 1 B. 20 C. 4 D. 8 E. 16 The result is $\displaystyle 4\times\frac{1}{2}=2$, right? Or did they make a typo again, considering if the B option was intended to be 2, the option from A to E forms a geometry sequence with ratio 2?
 October 8th, 2014, 05:42 AM #2 Senior Member     Joined: Apr 2014 From: Europa Posts: 584 Thanks: 177 Right !

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