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April 15th, 2014, 08:49 AM  #1 
Newbie Joined: Apr 2014 From: india Posts: 3 Thanks: 0  Solving equation without taking logarithm
hi guys can you tell me how can we take out the value of 10^y if the equation is 10^2y =25 without taking logarithm

April 15th, 2014, 09:06 AM  #2 
Senior Member Joined: Dec 2013 From: Russia Posts: 327 Thanks: 108 
Hint: $10^{2y}=\left(10^y\right)^2=\left(10^{y}\right)^{2}$.


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