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April 15th, 2014, 08:49 AM   #1
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Solving equation without taking logarithm

hi guys can you tell me how can we take out the value of 10^-y if the equation is 10^2y =25 without taking logarithm
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April 15th, 2014, 09:06 AM   #2
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Hint: $10^{2y}=\left(10^y\right)^2=\left(10^{-y}\right)^{-2}$.
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