My Math Forum Can you guys solve this?

 Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion

February 1st, 2016, 07:14 PM   #31
Senior Member

Joined: Jan 2014
From: The backwoods of Northern Ontario

Posts: 371
Thanks: 68

Quote:
 Originally Posted by Denis Geezzz...can someone pleeezzzze close this thread...
Okay, Denis. I'll close it with the final line:

1 × 2 = 2 (or in the order that you had it: 2 × 1 = 2)

Last edited by Timios; February 1st, 2016 at 07:18 PM.

 October 28th, 2016, 09:51 PM #32 Newbie   Joined: Jan 2016 From: at home Posts: 2 Thanks: 1 The '=' is a relation operator which is used for assignment, and although we most commonly assign equality, it doesn't change what it truly is. That said ... It turns out the ‘?’ can be whatever we want it to be! Allow me to illustrate. Take for example, f(x)=(1/40)x^4-(13/20)x^3+(291/40)x^2-(553/20)x+42, and evaluate f(8), f(7), f(6), f(5), f(3). It turns out that: f(8)=56, f(7)=42, f(6)=30, f(5)=20, f(3)=9. Wait, what sorcery is this? Turns out that although the popular rule f(x)=x(x-1), which gives f(x)=6, satisfies the known values in the sequence, that f(x)=(1/40)x^4-(13/20)x^3+(291/40)x^2-(553/20)x+42 also satisfies them–except with a different value of f(3)! Here’s another one that also works but gives f(3)=12: f(x)=(1/20)x^4-(13/10)x^3+(271/20)x^2-(543/10)x+84 And here is one where f(3)=π f(x)=(1/120)(π-6)x^4-(13/60)(π-6)x^3+(1/120)(251π-1386)x^2+(1/60)(3138-533π)x+14(π-6) Finally, in general if you want the ‘?’=k, i.e., f(3)=k where k is the value of your choice, then (1/120)(k-6)x^4-(13/60)(k-6)x^3+(1/120)(251k-1386)x^2+(1/60)(3138-533k)x+14(k-6) More details here: https://www.scribd.com/doc/260182194...tary-Sequences For a non-polynomial rule see here: Last edited by skipjack; December 13th, 2016 at 08:22 PM.

 Tags guys, solve

,

,

,

,

,

,

,

,

,

,

,

,

,

,

# do u solve it

Click on a term to search for related topics.
 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post RedDevil96 Physics 0 February 7th, 2014 03:12 AM PLUS-MINUS Algebra 2 December 23rd, 2013 05:34 PM anonimnystefy New Users 6 February 4th, 2013 05:37 AM colerelm New Users 2 February 7th, 2012 03:40 PM KateDaring52 New Users 3 July 6th, 2011 05:37 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top