My Math Forum  

Go Back   My Math Forum > High School Math Forum > Elementary Math

Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion

Thanks Tree3Thanks
LinkBack Thread Tools Display Modes
February 1st, 2016, 07:14 PM   #31
Senior Member
Joined: Jan 2014
From: The backwoods of Northern Ontario

Posts: 371
Thanks: 68

Originally Posted by Denis
Geezzz...can someone pleeezzzze close this thread...
Okay, Denis. I'll close it with the final line:

1 × 2 = 2 (or in the order that you had it: 2 × 1 = 2)

Last edited by Timios; February 1st, 2016 at 07:18 PM.
Timios is offline  
October 28th, 2016, 09:51 PM   #32
Joined: Jan 2016
From: at home

Posts: 2
Thanks: 1

The '=' is a relation operator which is used for assignment, and although we most commonly assign equality, it doesn't change what it truly is. That said ...

It turns out the ‘?’ can be whatever we want it to be!

Allow me to illustrate. Take for example, f(x)=(1/40)x^4-(13/20)x^3+(291/40)x^2-(553/20)x+42, and evaluate f(8), f(7), f(6), f(5), f(3). It turns out that:


Wait, what sorcery is this? Turns out that although the popular rule f(x)=x(x-1), which gives f(x)=6, satisfies the known values in the sequence, that f(x)=(1/40)x^4-(13/20)x^3+(291/40)x^2-(553/20)x+42 also satisfies them–except with a different value of f(3)!

Here’s another one that also works but gives f(3)=12:

And here is one where f(3)=π

Finally, in general if you want the ‘?’=k, i.e., f(3)=k where k is the value of your choice, then

More details here:
For a non-polynomial rule see here:

Last edited by skipjack; December 13th, 2016 at 08:22 PM.
acubed123 is offline  

  My Math Forum > High School Math Forum > Elementary Math

guys, solve

Search tags for this page
Click on a term to search for related topics.
Thread Tools
Display Modes

Similar Threads
Thread Thread Starter Forum Replies Last Post
solve this guys RedDevil96 Physics 0 February 7th, 2014 03:12 AM
Guys, how can I solve this simple task? PLUS-MINUS Algebra 2 December 23rd, 2013 05:34 PM
Hi guys anonimnystefy New Users 6 February 4th, 2013 05:37 AM
Hey guys colerelm New Users 2 February 7th, 2012 03:40 PM
hi guys KateDaring52 New Users 3 July 6th, 2011 05:37 PM

Copyright © 2018 My Math Forum. All rights reserved.