
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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May 8th, 2013, 03:38 PM  #1 
Senior Member Joined: Jan 2012 Posts: 721 Thanks: 7  Find how much of each of tea he bought.
A shopkeeper bought tea at N2.40 per kg; and mixed it with twice as much tea at N2 per kg. He sold the mixure at N2.60 per kg and gained N5.60 on the transaction. Find how much of each of tea he bought. A shopkeeper bought tea at N2.40 per kg; and mixed it with twice as much tea at N2 per kg. Let the mass of the tea he bought at first be given as m. When he mixed it twice as much tea, he had 2m. > m + 2m = 2.40 + 4.8 > 3m = 7.2 He sold the mixure at N2.60 per kg and gained N5.60. 3m = 7.8 + 5.60 > 3m = 13.4 I know I have made an error already. But how can I express the problem, so that it will be more easier to solve? 
May 8th, 2013, 04:56 PM  #2  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 407  Re: Find how much of each of tea he bought. Hello, Chikis! Quote:
He bought kg of Brand A at $2.40.kg. [color=beige]. . [/color]This cost him dollars. He bought kg of Brand B at $2.00/kg. [color=beige]. . [/color]This cost him dollars. His total cost was: dollars. He sold the kg of tea at $2.60/kg. [color=beige]. . [/color]His revenue was: dollars. His profit was: dollars. [color=beige]. . [/color]We are told that his profit was $5.60. There is our equation! . . . Can you finish it?  
May 8th, 2013, 05:38 PM  #3 
Senior Member Joined: Jan 2012 Posts: 721 Thanks: 7  Re: Find how much of each of tea he bought.
@soroban, Yes, I can finish it now. Thank you. 

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