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May 4th, 2013, 11:52 AM   #1
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How much water did each tank contain originally?

A water tank A contains 3 times as much water as another water tank B. When 25 liters are poured from tank A into B, there is now twice as much water in B as in tank A. How much water did each tank contain originally?

A water tank A contains 3 times as much water as another water tank B.

Let the water be in tank A 3w and that in tank B be w.
>

When 25 liters are poured from tank A into B, there is now twice as much water in B as in tank A.

3w - 25 = 2w

How much water did each tank contain originally?

I can solve the problem if only I understand the English or words of the problem correctly. Please can any one explain it to me?
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May 4th, 2013, 01:38 PM   #2
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Re: How much water did each tank contain originally?

Hello, Chikis!

Quote:
Water tank A contains 3 times as much water as another water tank B.
When 25 liters are poured from tank A into B, there is now twice as much water in B as in tank A.
How much water did each tank contain originally?



Code:
      |       |     |       |
      |-------|     |       |
      |       |     |       |
      |       |     |       |
      |  3b   |     |       |
      |       |     |-------|
      |       |     |   b   |
      *-------*     *-------*
          A             B


Code:
      |       |     |       |
      |       |     |-------|
      |       |     |       |
      |       |     |       |
      |-------|     | b+25  |
      |       |     |       |
      | 3b-25 |     |       |
      *-------*     *-------*
          A             B




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May 12th, 2013, 02:44 PM   #3
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Re: How much water did each tank contain originally?

I think I have no problem in obtaining 3b and b as amount of water in tank A and B respectively. So that the equation can be set like this 3b - 25 = b + 25.

Where the problem is now, is how to translate the statement, "there is now twice as much water in B as in tank A."

From my understanding, since the amount of water in tank A is now 3b - 25 and the amount of water in tank B is b + 25.

Please break the words for me so that I can understand. Does twice as much water in B means 2(b + 25)?

Does as in tank A, means equal to tank A i.e = 3b - 25
so that you can have the equation as 2(b + 25) = 3b - 25? I don't understand how you got your equation as
2(3b - 25) = b + 25, instead of the way am thinking. Or could the equations 2(b + 25) = 3b - 25 and 2(3b - 25) = b + 25 mean the same thing? Thank you.
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