My Math Forum Odd problem I can't solve....

 Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion

 April 5th, 2013, 10:15 AM #1 Newbie   Joined: Apr 2013 From: Manchester, England Posts: 4 Thanks: 0 Odd problem I can't solve.... Ok I have a problem I can't figure out....not sure if starring at a blank piece of paper and doodling is really helping so figured I woud ask here.... If you have x people and 2 tasks and the tasks both have different needs how would I decide how many people go on each task? i.e. 10 people need to dig 2 holes. 1 hole is twice as big as the other so twice as many people need to work on that hole. So I have 2 targets: hole-1 and hole-2 hole-1 == 100 (for example) and hole-2 == 200 In my head I know I need 6.5 people to work on hole-2 and 3.5 to work on hole-1. But how did I come to these values??? The equasion to get this is illuding me and driving me nuts lol
 April 5th, 2013, 10:31 AM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs Re: Odd problem I can't solve.... In your example, I would observe that 1 + 2 = 3, so 1/3 of 10 should be assigned to hole 1, and 2/3 of 10 should be assigned to hole 2.
 April 5th, 2013, 10:51 AM #3 Newbie   Joined: Apr 2013 From: Manchester, England Posts: 4 Thanks: 0 Re: Odd problem I can't solve.... Um didn't explain myself properly. I am trying to make an algorithm where hole-1 (x) and hole-2 (y) could change at any time meaning that x1 and y1 would have to also change. x1 and y1 being the number of people assigned to x and y holes respectively. This should end in a simple percentage. Thanks for the fast reply though I wasn't expecting such a quick response
 April 5th, 2013, 12:39 PM #4 Senior Member   Joined: Feb 2012 Posts: 628 Thanks: 1 Re: Odd problem I can't solve.... Another factor that often comes up in these types of problems is how fast each person works, but I am assuming in this case that everyone works at the same rate?
 April 5th, 2013, 04:01 PM #5 Newbie   Joined: Apr 2013 From: Manchester, England Posts: 4 Thanks: 0 Re: Odd problem I can't solve.... I eventually figured it out. No idea what I was thinking earlier because it was easy lol Constants: x= size of hole 1 y= size of hole 2 z= number of workers x+y/z == workers per unit workers on hole 1 = x* workers per unit workers of hole 2 = y* workers per unit Simple! One of those things that was so simple it illuded me lol This way the number of workers or the size of the holes could change and the right number of workers will always work at the same rate to dig the holes. (in case interested) I used this to adjust figures that would change randomly within an artificial intelligence script. Works like a dream now Thanks for your input.
 April 5th, 2013, 04:03 PM #6 Newbie   Joined: Apr 2013 From: Manchester, England Posts: 4 Thanks: 0 Re: Odd problem I can't solve.... Oops.... workers on hole 1 == x/ workers per unit and same for y that should have been.
 April 12th, 2013, 01:16 PM #7 Global Moderator   Joined: Dec 2006 Posts: 20,310 Thanks: 1980 Aren't your "workers per unit" actually "units per worker"?

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