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  • 1 Post By AplanisTophet
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September 28th, 2019, 02:57 AM   #1
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pls help

3n+21/n+3 is all the possible values so that n is a natural number and the final poduct of the equation is also a natural number
conor mcgregor is offline  
September 28th, 2019, 04:34 AM   #2
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Does $\frac{3n+21}{n+3} = \frac{n+7}{\frac{n}{3}+1}$?

If so, I think that means $n$ must always be divisible by 3, correct? Maybe not...?

We might also notice that $\frac{n+7}{n+3}$ must be a natural number, correct?

Do either of these things help? What have you tried so far?
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September 28th, 2019, 08:31 AM   #3
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Originally Posted by conor mcgregor View Post
Parentheses would also be nice. I am (reasonably) guessing that you want the form (3n + 21)/(n + 3). Details are important.

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