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September 12th, 2019, 10:31 PM   #1
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Please answer this two doubts from Cost price problem.

Rohan purchased a bike for Rs 54000. He sold it at a loss of 8 percent. With that money he again purchased another bike and sold it at a profit of 10 percent. What is his overall loss\profit?

Loss% = 8% = 8/100; Initial Price : Final Price = 100 : 92

Profit% = 10% = 1/10; Initial Price : Final Price = 10 : 11

Multiplying all Intial Price & Final Price
Intial Price : Final Price; = 1000 : 1012

Initial Price corresponds to Rohan’s CP;
1000 corresponds to 54000.
1 corresponds to 54.

Profit corresponds to difference between Final Price & Initial price; 1012 - 1000 = 12.
12*54 = 648.

How Initial Price corresponds to Rohan’s CP & how Profit corresponds to difference between Final Price & Initial price ?

How profit why not loss?
Ganesh Ujwal is offline  
 
September 12th, 2019, 11:48 PM   #2
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I couldn't follow your maths, I did it this way:
(54000 x 0.92 x 1.1) - 54000 = 648

Quote:
Originally Posted by Ganesh Ujwal View Post
How Initial Price corresponds to Rohan’s CP & how Profit corresponds to difference between Final Price & Initial price ?
I can't answer that as I don't understand your maths, but:

Quote:
Originally Posted by Ganesh Ujwal View Post
How profit why not loss?
If you lose 8% then gain 10%, the result is always a profit: 0.92 x 1.1 > 1
This is a 1.2% profit.
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September 13th, 2019, 02:57 AM   #3
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Quote:
Originally Posted by weirddave View Post
I couldn't follow your maths, I did it this way:
(54000 x 0.92 x 1.1) - 54000 = 648
Why did you subtract 54000 ?
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September 16th, 2019, 01:05 AM   #4
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OK, let me break it down.
54000 is the starting amount Rohan has. Ffter the first purchase and sell the new amount that Rohan has is 54000 x 0.92
After buying the 2nd bike and selling for a profit, Rohan now has 54000 x 0.92 x 1.1
So to find the overall profit, we need to subtract the initial sum that Rohan started with, which is 54000.
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