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September 12th, 2019, 10:31 PM  #1 
Senior Member Joined: Aug 2014 From: India Posts: 477 Thanks: 1  Please answer this two doubts from Cost price problem.
Rohan purchased a bike for Rs 54000. He sold it at a loss of 8 percent. With that money he again purchased another bike and sold it at a profit of 10 percent. What is his overall loss\profit? Loss% = 8% = 8/100; Initial Price : Final Price = 100 : 92 Profit% = 10% = 1/10; Initial Price : Final Price = 10 : 11 Multiplying all Intial Price & Final Price Intial Price : Final Price; = 1000 : 1012 Initial Price corresponds to Rohan’s CP; 1000 corresponds to 54000. 1 corresponds to 54. Profit corresponds to difference between Final Price & Initial price; 1012  1000 = 12. 12*54 = 648. How Initial Price corresponds to Rohan’s CP & how Profit corresponds to difference between Final Price & Initial price ? How profit why not loss? 
September 12th, 2019, 11:48 PM  #2  
Senior Member Joined: Apr 2014 From: UK Posts: 965 Thanks: 342 
I couldn't follow your maths, I did it this way: (54000 x 0.92 x 1.1)  54000 = 648 Quote:
If you lose 8% then gain 10%, the result is always a profit: 0.92 x 1.1 > 1 This is a 1.2% profit.  
September 13th, 2019, 02:57 AM  #3 
Senior Member Joined: Aug 2014 From: India Posts: 477 Thanks: 1  
September 16th, 2019, 01:05 AM  #4 
Senior Member Joined: Apr 2014 From: UK Posts: 965 Thanks: 342 
OK, let me break it down. 54000 is the starting amount Rohan has. Ffter the first purchase and sell the new amount that Rohan has is 54000 x 0.92 After buying the 2nd bike and selling for a profit, Rohan now has 54000 x 0.92 x 1.1 So to find the overall profit, we need to subtract the initial sum that Rohan started with, which is 54000. 

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