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 July 31st, 2019, 06:56 AM #1 Senior Member   Joined: Aug 2014 From: India Posts: 476 Thanks: 1 Explain this solution for this profit/loss problem? By selling an article at 80% of its MP, a merchant makes a loss of 12% what will be the profit /loss percent made by the merchant if he sells the article at 95% of its M.P? Sol: 80% is equated to 88 95% is equated to 104.5 104.5 - 100 = 4.5 Why 80% is equated to 88 & 95% is equated to 104.5?? Last edited by Ganesh Ujwal; July 31st, 2019 at 06:58 AM. July 31st, 2019, 07:19 AM #2 Global Moderator   Joined: Dec 2006 Posts: 21,028 Thanks: 2259 80% of M.P. corresponds to 88% (i.e. 100% - 12%) of C.P. 88 × 95/80 = 104.5 exactly, so the answer is 4.5% (profit). July 31st, 2019, 07:36 AM #3 Senior Member   Joined: Aug 2014 From: India Posts: 476 Thanks: 1 How did you write this equation: 88 × 95/80 = 104.5? July 31st, 2019, 08:15 AM #4 Global Moderator   Joined: Dec 2006 Posts: 21,028 Thanks: 2259 When the selling price is changed from 80% of the marked price to 95% of the same marked price, it is multiplied by 95/80. The original selling price is 88% of the cost price (because the merchant is making a 12% loss). To get the corresponding percentage of the cost price after the selling price is multiplied by 95/80, one just multiplies that 88% by 95/80, which gives 104.5%. Anything over 100% of the cost price is profit, so there is a profit of 4.5% for the merchant after the price change. July 31st, 2019, 07:39 PM   #5
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Quote:
 Originally Posted by skipjack When the selling price is changed from 80% of the marked price to 95% of the same marked price, it is multiplied by 95/80.

Explain this fraction; 95/80 ;if something is changed into new thing, then fraction becomes something/new thing. in profit and loss problems?? July 31st, 2019, 10:54 PM #6 Global Moderator   Joined: Dec 2006 Posts: 21,028 Thanks: 2259 If v is the original selling price, v = 0.8 M.P. If w is the new selling price, w = 0.95 M.P. Hence both w = (0.95/0.8)v and w = v + 0.15 M.P. As the value of M.P. isn't given, the first equation is more useful. For a different profit/loss problem, the second equation might be more useful. Tags explain, problem, profit or loss, solution Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Gunjan Algebra 5 May 14th, 2015 08:54 AM aditya ranjan Elementary Math 6 October 25th, 2013 03:05 AM ANAMIKA Elementary Math 6 May 24th, 2013 03:07 AM maya007 Economics 1 August 20th, 2011 01:31 PM maya007 Number Theory 0 December 31st, 1969 04:00 PM

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