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July 30th, 2019, 07:31 AM  #1 
Senior Member Joined: Aug 2014 From: India Posts: 458 Thanks: 1  How profit% equation obtained?
Even after reducing the marked price of a transistor by Rs 32, a shopkeeper makes a profit of 15%. If the C.P be Rs 320., what % of profit would he have made if he had sold the transistor at M.P? Solution: profit% = 32/320*100 = 10% total profit = 15+10 = 25. How profit% equation obtained? Last edited by skipjack; July 30th, 2019 at 09:39 AM. 
July 30th, 2019, 09:51 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,921 Thanks: 2203 
The profit, as a percentage of the C.P., is (S.P.  C.P.)/C.P.×100%, so if the S.P. changes by an amount r, that percentage changes by (S.P.+ r  C.P.)/C.P.×100%  (S.P.  C.P.)/C.P.×100% = r/C.P.×100%, which is 32/320×100% for the change described.

July 30th, 2019, 11:14 PM  #3 
Senior Member Joined: Aug 2014 From: India Posts: 458 Thanks: 1 
How can you tell given question contains S.P. changes by an amount r? In the question, nowhere mentioned about S.P. There are two sentences in the question, how can you tell CP is 320 in both sentences? Last edited by Ganesh Ujwal; July 30th, 2019 at 11:25 PM. 

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