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July 18th, 2019, 06:57 AM   #1
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Still I should Amount as 7200?

Rs 6000 becomes Rs 7200 in 4 years. If the rate becomes 1.5 times of
itself, the amount of the same principal in 5 years will be:

Sol: Amount = 7200; S.I = A – P; S.I = 7200 -6000 = 1200.
→ 1200 = 6000*R*4/100
→ R = 5%
Now R is increased upto 1.5 times, i.e 7.50%

Now S.I = 6000*7.50/100*5; S.I = 2250.

Amount = P + S.I = 6000 + 2250 = 8250

If I change question like this: Rs 6000 becomes Rs 7200 in 4 years. If the rate becomes 1.5 times of itself, the S.I of the same principal in 5 years will be:

Still I should Amount as 7200?
Ganesh Ujwal is offline  
 
July 18th, 2019, 07:12 AM   #2
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Absolutely nothing has changed in the new scenario. SI = Rs 2250.
DarnItJimImAnEngineer is offline  
July 18th, 2019, 07:14 AM   #3
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Quote:
Originally Posted by DarnItJimImAnEngineer View Post
Absolutely nothing has changed in the new scenario. SI = Rs 2250.
Something 1 becomes Something 2.

Something 2 always taken as amount in S.I problems?
Ganesh Ujwal is offline  
July 18th, 2019, 08:27 AM   #4
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We can't guarantee that every textbook or author uses the same terminology.

The original question is ambiguous for a different reason - it isn't entirely clear whether the five-year period is instead of the four-year period or whether it starts when the four-year period ends, though the first of these possibilities is likely to be the intended interpretation.
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July 18th, 2019, 11:49 PM   #5
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The use of the word 'amount' is confusing, you have it as 7200 and 8250, you need to define it a little more. 'initial amount' and 'final amount' would be much better terminology.
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