
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
 LinkBack  Thread Tools  Display Modes 
May 26th, 2019, 10:07 PM  #1 
Senior Member Joined: Dec 2015 From: somewhere Posts: 729 Thanks: 98  Number of solutions
Given equation(with respect to x): $\displaystyle x^n +x=nx $ , how many real solutions the equation has ? $\displaystyle x\geq 0 \; $ and $\displaystyle n\in \mathbb{N} $. 
May 27th, 2019, 01:55 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 21,029 Thanks: 2259 
2

May 28th, 2019, 07:07 AM  #3 
Senior Member Joined: Dec 2015 From: somewhere Posts: 729 Thanks: 98 
By factorization of the equation : $\displaystyle n\cdot x $ is totally independent to a constant . So the number of real solutions is 2. 
May 28th, 2019, 11:13 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 21,029 Thanks: 2259 
Your reasoning is unclear. Does it always apply?

May 29th, 2019, 12:42 AM  #5 
Senior Member Joined: Dec 2015 From: somewhere Posts: 729 Thanks: 98  
May 29th, 2019, 05:42 AM  #6 
Global Moderator Joined: Dec 2006 Posts: 21,029 Thanks: 2259 
How exactly do you proceed in that way to your conclusion?


Tags 
number, solutions 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Number of Integral solutions  arybhatta01  Calculus  1  May 25th, 2019 08:26 PM 
Number of solutions  idontknow  Number Theory  5  December 31st, 2018 06:00 PM 
number of solutions  Nathalia  Trigonometry  3  September 29th, 2016 10:22 PM 
Number of Solutions  ishaanmj007  Algebra  4  May 16th, 2015 04:38 PM 
number of solutions.  earth  Math Events  3  July 8th, 2009 09:14 PM 