
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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March 26th, 2019, 08:45 AM  #1 
Newbie Joined: Mar 2019 From: Hyderabad Posts: 7 Thanks: 0  A person sold a chair at a loss of 20%. If he had sold it for Rs 50 more, he would ha
A person sold a chair at a loss of 20%. If he had sold it for Rs 50 more, he would have gained 5%. Find the cost price of the chair.

March 26th, 2019, 09:06 AM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,408 Thanks: 1310 
$p = c(10.2)$ $p+50 = c(1+0.05)$ you solve it 
March 27th, 2019, 05:53 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,485 Thanks: 2041 
The difference between a 20% loss and a 5% gain is 25%, so Rs 50 is 25% of the cost price.

April 11th, 2019, 05:27 PM  #4  
Senior Member Joined: Jan 2012 Posts: 739 Thanks: 7  Quote:
So 1% =( Rs 50)/5 = 10%. Because cost price = 100%. There you have it. cost price = Rs 10 x 100 = Rs 1000. Is that okay by you?  
April 11th, 2019, 06:08 PM  #5 
Global Moderator Joined: Dec 2006 Posts: 20,485 Thanks: 2041 
It wasn't sold for sold for Rs 50 more than cost price, but for Rs 50 more than a price that resulted in a 20% loss, i.e. 80% of cost price.

April 11th, 2019, 06:58 PM  #6 
Senior Member Joined: Jan 2012 Posts: 739 Thanks: 7  
April 11th, 2019, 07:10 PM  #7 
Senior Member Joined: Jan 2012 Posts: 739 Thanks: 7  
April 11th, 2019, 07:17 PM  #8 
Senior Member Joined: Jan 2012 Posts: 739 Thanks: 7  What do the p and c mean? Is that supposed to be profit and cost price respectively?
Last edited by skipjack; April 12th, 2019 at 05:41 AM. 
April 12th, 2019, 05:40 AM  #9 
Global Moderator Joined: Dec 2006 Posts: 20,485 Thanks: 2041 
Rs c is the cost price and Rs p is the price at which the chair was sold (at a 20% loss). Subtracting the first equation from the second gives 50 = 0.25c. 

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