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 January 3rd, 2019, 03:44 PM #1 Senior Member   Joined: Dec 2015 From: somewhere Posts: 721 Thanks: 97 Simple sequence Find n-th term or function $\displaystyle f(n)$ that defines the sequence $\displaystyle 2,2,0,0,0,....\; \;$ (infinite zeros after second term)
 January 3rd, 2019, 06:26 PM #2 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1039 Huh? Thanks from idontknow
 January 3rd, 2019, 06:39 PM #3 Global Moderator   Joined: Dec 2006 Posts: 21,026 Thanks: 2257 $\displaystyle f(n) = 1 - \frac{|2n - 5|}{2n - 5}$, where $n$ is a positive integer. Thanks from greg1313, topsquark and idontknow
 January 4th, 2019, 05:16 AM #4 Senior Member   Joined: Dec 2015 From: somewhere Posts: 721 Thanks: 97 Another one is $\displaystyle f(n)=n \lfloor \frac{2}{n} \rfloor$ Thanks from greg1313 and topsquark
 January 4th, 2019, 07:55 AM #5 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,690 Thanks: 2669 Math Focus: Mainly analysis and algebra $$f(n) = \begin{cases}2 & ( n \le 2 ) \\ 0 & (n \gt 2)\end{cases} \qquad n \in \mathbb N$$ Thanks from greg1313, topsquark, romsek and 1 others
 January 4th, 2019, 10:42 AM #6 Senior Member   Joined: Dec 2015 From: somewhere Posts: 721 Thanks: 97 Here comes the other one $\displaystyle f(n)=2\lfloor 2^{-1} +n^{-1} \rfloor$ Thanks from greg1313 and topsquark

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