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January 3rd, 2019, 03:44 PM  #1 
Senior Member Joined: Dec 2015 From: somewhere Posts: 514 Thanks: 80  Simple sequence
Find nth term or function $\displaystyle f(n)$ that defines the sequence $\displaystyle 2,2,0,0,0,....\; \; $ (infinite zeros after second term) 
January 3rd, 2019, 06:26 PM  #2 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,419 Thanks: 1025 
Huh?

January 3rd, 2019, 06:39 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,654 Thanks: 2087 
$\displaystyle f(n) = 1  \frac{2n  5}{2n  5}$, where $n$ is a positive integer.

January 4th, 2019, 05:16 AM  #4 
Senior Member Joined: Dec 2015 From: somewhere Posts: 514 Thanks: 80 
Another one is $\displaystyle f(n)=n \lfloor \frac{2}{n} \rfloor$

January 4th, 2019, 07:55 AM  #5 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,660 Thanks: 2635 Math Focus: Mainly analysis and algebra 
$$f(n) = \begin{cases}2 & ( n \le 2 ) \\ 0 & (n \gt 2)\end{cases} \qquad n \in \mathbb N$$

January 4th, 2019, 10:42 AM  #6 
Senior Member Joined: Dec 2015 From: somewhere Posts: 514 Thanks: 80 
Here comes the other one $\displaystyle f(n)=2\lfloor 2^{1} +n^{1} \rfloor$


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sequence, simple 
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