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December 11th, 2018, 11:01 PM   #1
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How to solve this

Hello sir
How to solve this

(1+a/b)^x = z/y
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December 12th, 2018, 12:14 AM   #2
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For which variable?
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December 12th, 2018, 12:22 AM   #3
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Hello sir
How to solve variable x
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December 12th, 2018, 12:44 AM   #4
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x = ln(z/y)/ln(1 + a/b)
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December 12th, 2018, 02:05 AM   #5
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Hello sir
Then what to do next step after natural log
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December 12th, 2018, 02:28 AM   #6
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Just add the logarithm to both sides
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December 12th, 2018, 03:19 AM   #7
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x = ln(z/y)/ln(1 + a/b)

how to remove log ln
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December 12th, 2018, 03:33 AM   #8
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$\displaystyle x=\log_{1+\frac ab}\left(\frac zy\right),\quad\frac ab>0$

Last edited by greg1313; December 12th, 2018 at 04:31 AM.
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December 12th, 2018, 07:09 AM   #9
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Quote:
Originally Posted by VRTTWETET View Post
Then what to do next step after natural log
You later posted "how to remove log ln".
You can use a logarithm with a logarithmic base of your choice, but you can't solve without using a logarithm. What logarithmic base would you find acceptable?
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December 12th, 2018, 09:46 PM   #10
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Hello sir
How it is solved
how the power are transferred

(1+r/12)^6×5662=5774

(1+r/12)^6=5774/5662

1+r/12=(5774/5662)^1/6
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