My Math Forum sqrt equation

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 December 11th, 2018, 01:19 PM #1 Senior Member   Joined: Dec 2015 From: iPhone Posts: 477 Thanks: 73 sqrt equation $\displaystyle \sqrt{5-x}=5-x^2$
 December 11th, 2018, 01:58 PM #2 Global Moderator   Joined: Dec 2006 Posts: 20,469 Thanks: 2038 Squaring gives $5 - x = 25 - 10x^2 + x^4$, so $x^4 - 10x^2 + x + 20 = 0$. Hence $(x^2 - x - 4)(x^2 + x - 5) = 0$. After solving that, check which of its roots satisfy the original equation. Thanks from topsquark and idontknow
 December 11th, 2018, 02:23 PM #3 Senior Member   Joined: Dec 2015 From: iPhone Posts: 477 Thanks: 73 I didnt notice that squaring gives a prod
 December 11th, 2018, 02:45 PM #4 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,290 Thanks: 1023 What's a "prod"?
 December 11th, 2018, 02:56 PM #5 Senior Member   Joined: Dec 2015 From: iPhone Posts: 477 Thanks: 73 Edit it , i meant product

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