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November 1st, 2018, 10:05 PM   #1
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How to solve percentage problem based on marks?

In an examination, 80% of the boys passed in English and 85% passed in mathematics, while 75% passed in both. If 45 boys failed in both. The number of boys who sat for the examination was.

Number of Boys pass % in English = 80%
Number of Boys pass % in Maths = 75%
Boys who passed in both English & Maths = 75%

After this how to proceed?
Ganesh Ujwal is offline  
 
November 2nd, 2018, 01:24 AM   #2
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I'd start by working out what % failed both, since we have that as an actual number of boys.
Since 80% passed English and 75% passed both, 5% passed English only.
Since 85% passed Maths and 75% passed both, 10% passed Maths only.

So, the % of boys who passed neither is All the boys minus those who passed both minus those who passed only one of the subjects:
100% - 75% - 5% - 10% = 10%

The next step should be easy....
weirddave is offline  
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