My Math Forum How to solve this Late/Early/Usual Time type problem?

 Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion

 October 26th, 2018, 03:56 AM #1 Senior Member   Joined: Aug 2014 From: India Posts: 343 Thanks: 1 How to solve this Late/Early/Usual Time type problem? A person reaches office 15 mins late when travelling speed of 40 km/hr. A person reaches office 10 mins early when travelling speed of 50 km/hr. How much time he should travel if he reaches office by 1 hour late? Overall distance = 25*40*50/10*60 = 83.33m First person's time without considering late = 83.33/40 = 2.08hr after this how to solve it? Last edited by Ganesh Ujwal; October 26th, 2018 at 03:59 AM.
 October 26th, 2018, 09:00 AM #2 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,145 Thanks: 1003 v = required speed to get to office on time t = required time to get to office on time @v...............vt................>t @40.........40(t+1/4)..........>t+1/4 (15 min = 1/4 hr) @50.........50(t-1/6)...........>t-1/6 (10 min = 1/6 hr) 40(t+1/4) = 50(t-1/6) Solve for t...then continue...
October 26th, 2018, 06:34 PM   #3
Senior Member

Joined: Aug 2014
From: India

Posts: 343
Thanks: 1

Quote:
 Originally Posted by Denis 40(t+1/4) = 50(t-1/6) Solve for t...then continue...
40t + 10 = 50t - 50/6
10t = 10 + 50/6
10t = 110/6
I got t = 1.83 hr.

After this, how to proceed?

 October 27th, 2018, 04:46 AM #4 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,145 Thanks: 1003 C'mon Ganesh. If it takes 1.83 hr to be on time, how long does it take to be 1 hour late?
October 27th, 2018, 08:11 AM   #5
Global Moderator

Joined: Dec 2006

Posts: 20,385
Thanks: 2011

Quote:
 Originally Posted by Ganesh Ujwal Overall distance = 25*40*50/10*60 = 83.33m
The overall distance unit should be km, not m.

Quote:
 Originally Posted by Ganesh Ujwal First person's time without considering late = 83.33/40 = 2.08hr
The time you found, 2.08 hr (or exactly 2 hr 5 min) includes being 15 min late, so the journey time for arrival on time is exactly 1 hr 50 min.

October 28th, 2018, 02:38 AM   #6
Senior Member

Joined: Aug 2014
From: India

Posts: 343
Thanks: 1

Quote:
 Originally Posted by skipjack The time you found, 2.08 hr (or exactly 2 hr 5 min) includes being 15 min late, so the journey time for arrival on time is exactly 1 hr 50 min.
But I need to find how much time he should travel if he reaches office by 1 hour late?

 October 28th, 2018, 05:01 AM #7 Global Moderator   Joined: Dec 2006 Posts: 20,385 Thanks: 2011 That would be exactly one hour more than the time found for arriving on time.
October 28th, 2018, 05:16 AM   #8
Math Team

Joined: Oct 2011

Posts: 14,145
Thanks: 1003

Quote:
 Originally Posted by Ganesh Ujwal But I need to find how much time he should travel if he reaches office by 1 hour late?
I already told you that: solve for t, then add 1 hour...

 Tags late or early or usual, problem, solve, time, type

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Ganesh Ujwal Elementary Math 11 July 10th, 2018 12:18 PM Ganesh Ujwal Elementary Math 2 June 18th, 2018 03:41 AM Ganesh Ujwal Elementary Math 2 April 27th, 2018 10:54 AM SolCon Algebra 11 January 24th, 2011 06:57 AM SolCon Calculus 1 December 31st, 1969 04:00 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top