
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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October 21st, 2018, 06:00 PM  #1 
Member Joined: Sep 2018 From: Japan Posts: 35 Thanks: 2  Pink and Green Ribbon
Ann had a pink ribbon and a green ribbon. The pink ribbon was twice as long as the green ribbon. After Ann use (1/3) of the pink ribbon and ( 3 and 1/4) m of the green ribbon, the length of the pink ribbon left was 4 times that of the green ribbon left. What was the length of the pink ribbon at first? My work: (I'm couldn't get it correct, but this is how far I got) Pink ribbon = p Green ribbon = G [1] The pink ribbon was twice as long as the green ribbon => p = 2g [2] After Ann use (1/3) of the pink ribbon and ( 3 and 1/4) m of the green ribbon, the length of the pink ribbon left was 4 times that of the green ribbon left. => 4(p  1/3) = g  (3 and 1/4) I got stuck there. I'm not sure for what I did for [2] was correct. 
October 21st, 2018, 06:29 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,264 Thanks: 1198 
$\dfrac{\frac {2p}{ 3}}{g\frac {13}{4}} = 4$ $\dfrac{\frac{4g}{3}}{\frac{4g13}{4}}=4$ $\dfrac{16g}{12g39}=4$ $4g = 12g  39$ $g = \dfrac{39}{8}m$ $p=2g = \dfrac{39}{4}m$ 
October 22nd, 2018, 09:34 AM  #3 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,791 Thanks: 970 
g = Green length [G].........g.......... [P]................2g................ [G]....g13/4... [P]............4g/3......... 4g / 3 = 4(g  13/4) 

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