My Math Forum  

Go Back   My Math Forum > High School Math Forum > Elementary Math

Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion


Thanks Tree1Thanks
  • 1 Post By romsek
Reply
 
LinkBack Thread Tools Display Modes
September 26th, 2018, 08:50 PM   #1
Newbie
 
Joined: Sep 2018
From: Japan

Posts: 27
Thanks: 2

Number of beads total

Siti had 135 more red beads than blue beads. After she used half of the red beads and 1/5 of the blue beads, there was an equal number of red beads and blue beads. How many beads did Siti have at first?

My work.

Number of red beads = R
Number of red beads = B

[1] Siti had 135 more red beads than blue beads => R = B + 135
[2] After she used half of the red beads and 1/5 of the blue beads, there was an equal number of red beads and blue beads =>(1/2)R = (4/5)B

My question. I'm not sure whether my equation for [2] is correct.

But I did this.

From [2], (1/2)R = (4/5)B => R = 8/5B

Then I plugged it up in [1]. (8/5)B = B + 134. => B = 225.

I then plugged B in 1. So R = 225 + 135. => R = 360.

Answer: B + R = 585.

Last edited by skipjack; September 27th, 2018 at 01:53 AM.
xoritos is offline  
 
September 26th, 2018, 09:50 PM   #2
Senior Member
 
romsek's Avatar
 
Joined: Sep 2015
From: USA

Posts: 2,122
Thanks: 1102

This is correct
Thanks from xoritos
romsek is offline  
Reply

  My Math Forum > High School Math Forum > Elementary Math

Tags
beads, number, total



Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
The total number of figures mared Algebra 3 May 29th, 2014 02:23 PM
Total number of combinations crone Advanced Statistics 5 July 26th, 2013 01:01 PM
What is the total number of string in ?* muhammadmasood Computer Science 7 September 14th, 2012 01:03 PM
Number of Necklace/Bracelets With Fixed Number of Beads UnreasonableSin Number Theory 2 June 13th, 2010 12:03 AM
find unique n number combination in total n number jsonliu Algebra 3 May 18th, 2010 05:01 PM





Copyright © 2018 My Math Forum. All rights reserved.