
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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September 26th, 2018, 08:50 PM  #1 
Newbie Joined: Sep 2018 From: Japan Posts: 27 Thanks: 2  Number of beads total
Siti had 135 more red beads than blue beads. After she used half of the red beads and 1/5 of the blue beads, there was an equal number of red beads and blue beads. How many beads did Siti have at first? My work. Number of red beads = R Number of red beads = B [1] Siti had 135 more red beads than blue beads => R = B + 135 [2] After she used half of the red beads and 1/5 of the blue beads, there was an equal number of red beads and blue beads =>(1/2)R = (4/5)B My question. I'm not sure whether my equation for [2] is correct. But I did this. From [2], (1/2)R = (4/5)B => R = 8/5B Then I plugged it up in [1]. (8/5)B = B + 134. => B = 225. I then plugged B in 1. So R = 225 + 135. => R = 360. Answer: B + R = 585. Last edited by skipjack; September 27th, 2018 at 01:53 AM. 
September 26th, 2018, 09:50 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,122 Thanks: 1102 
This is correct


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