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September 14th, 2018, 05:44 AM  #1 
Newbie Joined: Sep 2018 From: korea Posts: 18 Thanks: 1  Number of sheeps
A farmer rears sheep and chickens at his farm. The number of sheep is 1/3 the number of chickens. There are 96 fewer sheep legs than chicken legs. How many sheep are there at the farm? My work: Number of sheeps = S Number of Chickens = C We know that there is one third of sheeps than chickens. so, (1/3)S = C We know that there are 96 fewer sheep legs than chicken leg. so, 2C = 4S  96 I got stuck here and couldn't get the correct answer. 
September 14th, 2018, 06:07 AM  #2  
Math Team Joined: Jul 2011 From: Texas Posts: 2,767 Thanks: 1422  Quote:
Quote:
substitute $3S$ for $C$ in the last equation ... $\displaystyle 4S = 2(3S) + 96$ solve for $S$  
September 14th, 2018, 01:27 PM  #3  
Newbie Joined: Sep 2018 From: korea Posts: 18 Thanks: 1  I see where I made the mistake. One third of the total chicken. Quote:
Thank you. Last edited by xoritos; September 14th, 2018 at 02:26 PM.  
September 14th, 2018, 04:20 PM  #4 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,129 Thanks: 914 
C = 3S [1] 2C  4S = 96 [2] Substitute [1] in [2]: 2(3S)  4S = 96 6S  4S = 96 2S = 96 S = 48 : C = 3S = 144 I think Skeeter made a typo... ...hmmm, think I'll have a snack of chicken legs Last edited by Denis; September 14th, 2018 at 04:23 PM. 
September 15th, 2018, 12:49 AM  #5 
Global Moderator Joined: Dec 2006 Posts: 19,542 Thanks: 1751 
As each sheep's 4 legs are 2 fewer than 3 chickens' 6 legs, number of sheep = 96/2 = 48.

September 15th, 2018, 05:05 AM  #6 
Newbie Joined: Sep 2018 From: korea Posts: 18 Thanks: 1 
Thank you.


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