July 9th, 2018, 04:53 AM  #1 
Senior Member Joined: Aug 2014 From: India Posts: 310 Thanks: 1  How to solve apart problems?
A and B leave their places and start moving towards each other. If they are 50m apart after both 2 minutes and 3 minutes, how far apart are their places? I draw the diagram of this problem: After this. how to proceed from here? 
July 9th, 2018, 06:12 AM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,204 Thanks: 511 Math Focus: Calculus/ODEs 
I would write: $\displaystyle d50=2v$ $\displaystyle d+50=3v$ Can you proceed? 
July 9th, 2018, 07:26 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 19,513 Thanks: 1744 
Further information is needed, else it needs to be assumed that $v$ is a constant.

July 9th, 2018, 08:11 AM  #4 
Senior Member Joined: Aug 2014 From: India Posts: 310 Thanks: 1  
July 9th, 2018, 08:17 AM  #5 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,204 Thanks: 511 Math Focus: Calculus/ODEs 
After 2 minutes, the combined distance covered by the two moving objects is 50 m less than their initial distance apart (which I've labeled d).

July 9th, 2018, 07:44 PM  #6  
Senior Member Joined: Aug 2014 From: India Posts: 310 Thanks: 1  Quote:
Are you referring to this: combined distance = AC + DB?  
July 9th, 2018, 07:49 PM  #7 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,204 Thanks: 511 Math Focus: Calculus/ODEs 
Yes, the combined distance covered by A and B after 2 minutes is the entire initial distance between them minus the gap between them.

July 10th, 2018, 05:11 AM  #8 
Senior Member Joined: Aug 2014 From: India Posts: 310 Thanks: 1  
July 10th, 2018, 05:51 AM  #10  
Senior Member Joined: Aug 2014 From: India Posts: 310 Thanks: 1  Quote:
I didn't get the idea, but I understand the diagram. Last edited by skipjack; July 10th, 2018 at 11:47 AM.  

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