July 4th, 2018, 08:34 AM  #11 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,140 Thanks: 915  
July 13th, 2018, 10:20 AM  #12  
Math Team Joined: Jan 2015 From: Alabama Posts: 3,261 Thanks: 894  Quote:
Last edited by skipjack; July 14th, 2018 at 02:06 AM.  
July 13th, 2018, 11:14 AM  #13 
Senior Member Joined: Aug 2012 Posts: 2,010 Thanks: 574 
Consider a spherical cow.

July 13th, 2018, 11:36 AM  #14 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,140 Thanks: 915  
July 14th, 2018, 02:08 AM  #15  
Global Moderator Joined: Dec 2006 Posts: 19,546 Thanks: 1754  Quote:
i.e. (number of cows) = k/(number of days), where k is a constant. Quote:
(number of cows) = k/(number of days) + p, where k and p are constants, implies a unique solution, namely k = 1200 and p = 20. Using those values and substituting number of days = 10, one gets the expected answer that number of cows = 140.  

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