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Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion


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July 2nd, 2018, 09:29 AM   #1
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Hardest elementary equations

We all know elementary equations are easy, but I'm stuck on this one below:
$\displaystyle n!=6 \; \; \; $ for $\displaystyle n\in N$
Solve it without inspection (I mean not saying direct n=3).

Last edited by skipjack; July 2nd, 2018 at 10:54 AM.
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July 2nd, 2018, 12:09 PM   #2
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What is an elementary equation? Why is this equation such a beast?
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July 2nd, 2018, 02:24 PM   #3
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Brute force is trivial. 1!=1, 2!=2, 3!=6.
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July 2nd, 2018, 02:40 PM   #4
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The proper divisors of 6 are 1, 2 and 3, so n = 3.
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July 2nd, 2018, 02:47 PM   #5
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1*2 = 2; 2*3 = 6; whoa!
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