
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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July 2nd, 2018, 08:29 AM  #1 
Senior Member Joined: Dec 2015 From: Earth Posts: 232 Thanks: 26  Hardest elementary equations
We all know elementary equations are easy, but I'm stuck on this one below: $\displaystyle n!=6 \; \; \; $ for $\displaystyle n\in N$ Solve it without inspection (I mean not saying direct n=3). Last edited by skipjack; July 2nd, 2018 at 09:54 AM. 
July 2nd, 2018, 11:09 AM  #2 
Senior Member Joined: May 2016 From: USA Posts: 1,052 Thanks: 431 
What is an elementary equation? Why is this equation such a beast?

July 2nd, 2018, 01:24 PM  #3 
Global Moderator Joined: May 2007 Posts: 6,540 Thanks: 591 
Brute force is trivial. 1!=1, 2!=2, 3!=6.

July 2nd, 2018, 01:40 PM  #4 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,823 Thanks: 1049 Math Focus: Elementary mathematics and beyond 
The proper divisors of 6 are 1, 2 and 3, so n = 3.

July 2nd, 2018, 01:47 PM  #5 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,765 Thanks: 860 
1*2 = 2; 2*3 = 6; whoa!


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