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 July 2nd, 2018, 09:29 AM #1 Senior Member   Joined: Dec 2015 From: iPhone Posts: 387 Thanks: 61 Hardest elementary equations We all know elementary equations are easy, but I'm stuck on this one below: $\displaystyle n!=6 \; \; \;$ for $\displaystyle n\in N$ Solve it without inspection (I mean not saying direct n=3). Last edited by skipjack; July 2nd, 2018 at 10:54 AM.
 July 2nd, 2018, 12:09 PM #2 Senior Member   Joined: May 2016 From: USA Posts: 1,306 Thanks: 549 What is an elementary equation? Why is this equation such a beast?
 July 2nd, 2018, 02:24 PM #3 Global Moderator   Joined: May 2007 Posts: 6,684 Thanks: 658 Brute force is trivial. 1!=1, 2!=2, 3!=6.
 July 2nd, 2018, 02:40 PM #4 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,912 Thanks: 1110 Math Focus: Elementary mathematics and beyond The proper divisors of 6 are 1, 2 and 3, so n = 3.
 July 2nd, 2018, 02:47 PM #5 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,959 Thanks: 991 1*2 = 2; 2*3 = 6; whoa!

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