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 June 16th, 2018, 05:34 AM #1 Senior Member   Joined: Aug 2014 From: India Posts: 341 Thanks: 1 How to solve this coding problem? In a certain code @ represents 0, # represents 1, @ represents 2 and ## represents 3 and so on. Which of the following represents 13 in this code language? a) #@#@ b) ##@@ c) ###@ d) ##@# e) ### 1 means # and ## means 3, combining them. It looks ###. My answer is ###, but it is wrong. Right answer is option D. How so?
 June 16th, 2018, 05:46 AM #2 Member   Joined: Aug 2017 From: India Posts: 48 Thanks: 2 It seems to be simple binary representation ##@# ---> 1 1 0 1 (Binary) -> 13(Decimal)
June 16th, 2018, 05:58 AM   #3
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Quote:
 Originally Posted by MathsLearner123 It seems to be simple binary representation ##@# ---> 1 1 0 1 (Binary) -> 13(Decimal)
How 1101 equals to 13?

 June 16th, 2018, 06:04 AM #4 Member   Joined: Aug 2017 From: India Posts: 48 Thanks: 2 Can you please search for Binary to Decimal conversion.
June 16th, 2018, 06:19 AM   #5
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Quote:
 Originally Posted by MathsLearner123 It seems to be simple binary representation ##@# ---> 1 1 0 1 (Binary) -> 13(Decimal)
How you got the idea of binary to decimal conversion?

 June 16th, 2018, 06:33 AM #6 Member   Joined: Aug 2017 From: India Posts: 48 Thanks: 2 May be experience.
June 16th, 2018, 08:54 AM   #7
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Quote:
 Originally Posted by Ganesh Ujwal In a certain code @ represents 0, # represents 1, @ represents 2 and ## represents 3 and so on.
I assume that was intended to say that #@ represents 2.

June 16th, 2018, 04:04 PM   #8
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Quote:
 Originally Posted by Ganesh Ujwal How you got the idea of binary to decimal conversion?
oh FFS at this point there is no way you aren't trolling.

 June 20th, 2018, 06:19 AM #9 Senior Member   Joined: Apr 2014 From: Glasgow Posts: 2,132 Thanks: 717 Math Focus: Physics, mathematical modelling, numerical and computational solutions Decimal system -> each digit represents powers of ten (read right to left) e.g. look at the decimal number 257 $\displaystyle 257 = 7 \times 10^0 + 5 \times 10^1 + 2 \times 10^2$ Binary system -> each digit represents powers of two (read right to left) $\displaystyle 1101 = 1 \times 2^0 + 0 \times 2^1 + 1 \times 2^2 + 1 \times 2^3$ We can calculate this using decimal notation: $\displaystyle 1 \times 2^0 + 0 \times 2^1 + 1 \times 2^2 + 1 \times 2^3 = 1 + 4 + 8 = 13$ There are websites which have very good ways of explaining binary and decimal number systems.

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