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April 27th, 2018, 10:07 AM   #1
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"Percentage Greater Than...."

The wording of this problem is confusing me with the "percentage greater than"....Can you please help me figure it out?

"In a parking garage, the number of SUV's is 40% greater than the number of non-SUV's. Lisa counted 98 SUV's in the garage. How many vehicles are in the garage?"

So is it correct that # of SUV's = 1.4 x # of non-SUV's? The words confuse me. But that is how I understand it, which would mean that
98 = 1.4n
n = 70, so 98 + 70 = 168 total cars

Is this correct?


Similarly, I am thrown off by this wording:

"An animal shelter houses only cats and dogs and there are 25% more cats than dogs. If there are 40 cats, how many dogs are there and how many total animals?"

Is it accurate that c = 1.25d, so d = 30?

I guess I get thrown off because if these are right (c=40, d=30), then if we look at the percentages of the total (40/70 = 57% and 30/70 = 43%, and the difference between those two percentages is not 25%. So is something wrong or is that not a right way to test the answer?

Thank you!
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April 27th, 2018, 10:40 AM   #2
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Quote:
Originally Posted by mjsilverfly View Post
n = 70, so 98 + 70 = 168 total cars

Is this correct?
Yes.

Quote:
Originally Posted by mjsilverfly View Post
Is it accurate that c = 1.25d, so d = 30?
It's correct that c = 1.25d, but that implies that d = 32. There are 72 animals in total.
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April 27th, 2018, 01:06 PM   #3
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OK, thank you. So am I misunderstanding how to test that I did the question right?.... If there are 72 total animals and 40 are cats and 32 are dogs....then 40/72 = 56% and 32/72 = 44%, but this doesn't reflect that there are 25% more cats than dogs. Wouldn't 0.44+0.25 have to equal 0.56 for that?
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April 27th, 2018, 01:25 PM   #4
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As 40/32 = 1.25, 40 is 25% more than 32.
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April 28th, 2018, 07:20 AM   #5
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"25% more cats than dogs" means that the number of cats, c, is 1.25 times the number of dogs, d: c= 1.25d. We are told that there are 40 cats so c= 40= 1.25 d. Divide both sides by 1.25= 5/4, which is the same as multiplying both sides by 4/5, to determine the number of dogs.
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