 My Math Forum How to solve this "time and distance" concept problem?

 Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion

 April 27th, 2018, 09:14 AM #1 Senior Member   Joined: Aug 2014 From: India Posts: 365 Thanks: 1 How to solve this "time and distance" concept problem? A and B start together from city P to city Q with respective speeds in the ratio 3:2 . If B takes $2\dfrac{1}{2}$ hours more than A to reach Q, then how much time does A take to reach Q? Ans: 5 hours I am stuck at this problem, I know distance =speed x time. Respective speed means 3x -2x = x April 27th, 2018, 09:44 AM #2 Senior Member   Joined: Sep 2015 From: USA Posts: 2,468 Thanks: 1342 respective speeds in the ratio 3:2 means that if A travels with speed $v$ then B travels with speed $\dfrac 2 3 v$ let $d$ be the distance between P and Q $\dfrac{d}{\frac 2 3 v}= \dfrac{d}{v}+\dfrac 5 2$ $\dfrac 3 2 \dfrac d v - \dfrac d v = \dfrac 5 2$ $\dfrac 1 2 \dfrac d v = \dfrac 5 2$ $T = \dfrac d v = 5$ and $T$ is the time it takes A to get from P to Q Thanks from Country Boy April 27th, 2018, 10:54 AM #3 Global Moderator   Joined: Dec 2006 Posts: 20,757 Thanks: 2138 As the speeds of A and B are in the ratio 3:2, their times are in the ratio 2:3 respectively. Those times differ by 1, which you are told represents 2 1/2 hours, so A's time is 2 times 2 1/2 hours, which is 5 hours. This assumes that they take the same route from city P to city Q (or routes of the same length). Thanks from Country Boy Tags concept, problem, solve, time and distance Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Eulerking500 Math 16 January 6th, 2017 05:01 PM dkcox Number Theory 1 December 27th, 2013 02:04 PM SedaKhold Calculus 0 February 13th, 2012 11:45 AM wawar05 Number Theory 6 December 5th, 2011 04:39 AM katie0127 Advanced Statistics 0 December 3rd, 2008 01:54 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top      