
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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April 17th, 2018, 08:53 AM  #1 
Senior Member Joined: Aug 2014 From: India Posts: 332 Thanks: 1  A salesman sells an article at 8% loss
A salesman sells an article at 8% loss. Had he bought the article at 12% less and and sold it at 26 more, he would have made a profit of $11\dfrac{1}{9}$% Find the new selling price of the article. Solution: Let the cost price of the article be 100c Selling price of the article = 92 c New cost price = 88c New selling price = 92c + 26 Given $92c + 23 = \dfrac{10}{9}\times88c \rightarrow c = 4.5$ $\therefore$ Required new selling price = 92 x 4.5 + 26 = 440 I have two questions: How new selling price is 92c + 26 rather than 88c + 26? How $\dfrac{10}{9}$ is obtained? Last edited by Ganesh Ujwal; April 17th, 2018 at 09:05 AM. 
April 17th, 2018, 04:29 PM  #2  
Math Team Joined: Jan 2015 From: Alabama Posts: 3,261 Thanks: 894  Quote:
Quote:
Last edited by Country Boy; April 17th, 2018 at 04:45 PM.  
April 17th, 2018, 06:09 PM  #3 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,314 Thanks: 935 
Ganesh, are your problems translated from another language?

April 17th, 2018, 06:50 PM  #4 
Senior Member Joined: Aug 2014 From: India Posts: 332 Thanks: 1  
April 17th, 2018, 06:57 PM  #5 
Senior Member Joined: Aug 2014 From: India Posts: 332 Thanks: 1  
April 18th, 2018, 09:34 PM  #6 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,314 Thanks: 935  
April 18th, 2018, 10:15 PM  #7  
Senior Member Joined: Aug 2014 From: India Posts: 332 Thanks: 1  Quote:  

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