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April 12th, 2018, 07:16 PM  #1 
Senior Member Joined: Aug 2014 From: India Posts: 310 Thanks: 1  A Milk solution of 60 litres contain....
A Milk solution of 60 litres contains 80% milk. How many litres of another milk solution containing 90% milk should be added to make an 84% milk solution? [Ans: 40 lit] I tried: $\dfrac {80}{100}\times \dfrac {M}{60} $ = $\dfrac {M}{25}$ calculation of second sentence: $\dfrac {M}{60}\times \dfrac {84}{100}$ = $\dfrac {21 M}{1500}$ calculation of first part in second sentence: $ \dfrac {M}{60}\times \dfrac {90}{100}$ Final equation: $ \dfrac {M}{60}\times \dfrac {90}{100} = \dfrac {M}{25}  \dfrac {21 M}{1500}$ I gone too far, is my approach right or wrong? if wrong, tell me the correct procedure. Last edited by Ganesh Ujwal; April 12th, 2018 at 07:24 PM. 
April 12th, 2018, 07:58 PM  #2 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,110 Thanks: 908  Code: 60 : 80 x : 90  60+x : 84 4800 + 90x = 84(60 + x) 4800 + 90x = 5040 + 84x Can you finish it? 
April 12th, 2018, 08:11 PM  #3 
Senior Member Joined: Aug 2014 From: India Posts: 310 Thanks: 1  You need to tell me why is my approach wrong otherwise feel free to ignore this question. I am following this equation: $\text{Concentration} = \dfrac{\text{Amount of milk}}{\text{Total amount of liquid}}$ Last edited by Ganesh Ujwal; April 12th, 2018 at 08:14 PM. 
April 13th, 2018, 04:30 AM  #4 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,110 Thanks: 908  Code: QUANTITY PERCENTAGE a : u b : v  a+b : w I agree with you when you said you're not dumb, so I'm sure you can figure out (by using above) why your approach is not the correct approach. Have a good day. 

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